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qwelly [4]
3 years ago
9

Please help with this Piecewise problem!!

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

You might be interested in
Number 20. if a and b are integers and a &gt; b, then l a l &gt; l b l
raketka [301]

.   Answer: I am pretty sure sometimes

Step-by-step explanation: if a = 6 and B = - 7, if you put them l a l > | b |

It makes them both positive so sometimes is the most probable answer .

( Sorry if it’s wrong)

6 0
3 years ago
Read 2 more answers
The locus of points in a plane 1 unit from the point (0,0)
xeze [42]

Answer:

x² + y² = 1

Step-by-step explanation:

A circle is the locus of a point such that its distance from a fixed point (known as the origin) is always constant. The general equation of a circle is given as:

(x-h)^2+(y-k)^2=r^2

Where (h, k) is the center of the circle and r is the radius of the circle.

Given that the plane is 1 unit from the point (0,0). Therefore the radius of the circle is 1 unit and the center of the circle is (0, 0). Therefore the equation of the circle is:

(x-0)^2+(y-0)^2=1^2\\\\x^2+y^2=1

3 0
3 years ago
how many 3 element subsets of {1, 2, 3, 4, 5, 6, 7, 8, ,9, 10, 11} are there for which the sum of the elements in the subset is
AURORKA [14]

Answer:

There are 155 ways in which these elements casn occur.

Step-by-step explanation:

We want 3 element subsets whose sum are multiples of 3

1+2+3= 6

1+2+6= 9

1+2+9= 12

1+9+11=21

1+3+5=9

1+4+8=12

1+5+6=12

1+6+8=15

1+7+10=18

1+8+9=18

1+9+11=21

2+3+7=12

2+4+6=12

2+4+9=15

2+5+11=18

2+6+7=15

2+7+9=18

2+8+5=15

2+8+11=21

2+9+10=21

3+6+9= 18

3+9+11=21

3+10+11=24

6+9+10=27

6+8+11=27

6+7+11=24

7+8+9= 24

8+9+10=27

7+9+11=27 .........

We have 11 elements

We need a combination of 3

The combinations can be in the form

even+ even+ odd

odd+odd+odd

even + odd+odd

So there are 3 ways in which these elements can occur

Total number of combinations with  3 elements =11C3= 165

There are 6 odd numbers and 5 even numbers.

Number of subsets with 3 odd numbers = 6C3= 20

Number of two even numbers and 1 odd number = 5C2*6C1=10*6= 60

Number of 2 odd and 1 even number = 6C2* 5C1= 5*15= 75

So 20+60+75=155

There are 155 ways in which this combination can occur

6 0
3 years ago
Convert 30 kilometers to miles?
Anna11 [10]
18.641 Miles is your answer
Hope this helps
7 0
3 years ago
Read 2 more answers
Solve 3- x/2&gt;_15<br> A. XS-24<br> B. X2-24<br> C. X2-6<br> D. XS 6
ch4aika [34]

Answer: x ≥ -24

Step-by-step explanation:

I think the equation is supposed to be written as an inequality.

3 - x/2 ≥ 15

Step 1: Subtraction property of equality

-x/2 ≥ 12

Step 2: Multiplication property of equality

-x ≥ 24

Step 3: Multiplication property of equality

x ≥ -24

8 0
3 years ago
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