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qwelly [4]
2 years ago
9

Please help with this Piecewise problem!!

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

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Find the value of 3a^2+2b, If a=3 and b = 4.<br><br>An explanation would be great.
vichka [17]

Answer:

=35

Step-by-step explanation:

3(3) ^2 + 2(4)

= 3(9) + 8

= 35

Where you see a, substitute with 3 and where you see b, substitute with 4

Just follow the steps above.

8 0
2 years ago
Read 2 more answers
For the function f(x) = x^2+ 3, what are the outputs for the inputs -3, 2, 0, and 5?
AysviL [449]

Answer:

F(-3)=12

F(2)=7

F(0)=3

F(5)=28

Step-by-step explanation:

8 0
3 years ago
Factor -22 out of 15.4b -6.6
valina [46]

Answer:

-7b+3

Step-by-step explanation:

first step you will find numbers if you take -2.2 to get those numbers

7 0
2 years ago
BRO PLS I HAVE TO PASS THIS (click for question) 20 POINTS!
Masja [62]

Answer:

D, E.

Step-by-step explanation:

<u>Simplify</u><u> </u><u>the</u><u> </u><u>expression</u><u> </u><u>inside</u><u> </u><u>the</u><u> </u><u>parentheses</u><u>:</u>

3(23 + 18) < 6a

3(41) < 6a

<u>Multiply:</u>

123 < 6a

<u>Substitute each value provided for a:</u>

Opt A. 123 < 6(18) = 123 < 108. Incorrect option.

Opt B. 123 < 6(19) = 123 < 114. Incorrect option.

Opt C. 123 < 6(20) = 123 < 120. Incorrect option.

Opt D. 123 < 6(22) = 123 < 132. Correct option.

Opt E. 123 < 6(24) = 123 < 144. Correct option.

3 0
2 years ago
Someone please help me with this​
Sedbober [7]

Answer:

The area of the shaded figure is:

  • <u>20 units^2</u>

Step-by-step explanation:

To obtain the area of the shaded figure, first, you must calculate this as a rectangle, with the measurements: wide (4 units), and long (6 units):

  • Area of a rectangle = long * wide
  • Area of a rectangle = 6 * 4
  • Area of a rectangle = 24 units^2

How the figure isn't a rectangle, you must subtract the triangle on the top, so, now we calculate the area of that triangle with measurements: wide (4 units), and height (2 units):

  • Area of a triangle = \frac{wide*height}{2}
  • Area of a triangle = \frac{4*2}{2}
  • Area of a triangle =\frac{8}{2}
  • Area of a triangle = 4 units^2

In the end, you subtract the area of the triangle to the area of the rectangle, to obtain the area of the shaded figure:

  • Area of the shaded figure = Area of the rectangle - Area of the triangle
  • Area of the shaded figure = 24 units^2 - 4 units^2
  • <u>Area of the shaded figure = 20 units^2</u>

I use the name "units" because the exercise doesn't say if they are feet, inches, or another, but you can replace this in case you need it.

5 0
2 years ago
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