Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.
Answer:
f(x) = -2x+5
f(x+h) = -2x -2h +5
g(x) = -4x-2
g(x+h) = -4x -4h -2
h(x) = 4x^2+1
h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1
Q(x) = -3x^2 +4
Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4
The answer to the question
Answer:

Step-by-step explanation:
Notice that we are in the presence of an arithmetic sequence (there is a common difference of 6 between a term and the next). So thisis an arithmetic sequence with first term
. and common difference "<em>d</em>" = 6.
Recall now the formula for the nth term (
) of an arithmetic sequence:

Then, using our values in the formula, we get:
