Answer:
a) t-test for two independent samples
b) For this case we have two different samples and both are less than 30 and we don't have any info about the populationd deviation's. So for this case the most appropiate test is the t-tes for two independent samples
Step-by-step explanation:
The independent t-test, is known as two sample t-test or independent-samples t-test, is an statistical test used to " determines whether there is a statistically significant difference between the means in two unrelated groups"
The system of hypothesis could be on this case like this:
Null hypothesis: 
Alternative hypothesis: 
Or equivalently:
Null hypothesis: 
Alternative hypothesis: 
The statistic to check the hypothesis is given by:

And this statistic follows a t distribution with degrees of freedom 
We can check the hypothesis using the p value method or the critical approach, but we need to have a significance level.
Part a
i) t-test for two independent samples
Part b
Explain the rationale for your selection in (a). Specifically, why would this be the appropriate statistical approach?
For this case we have two different samples and both are less than 30 and we don't have any info about the populationd deviation's. So for this case the most appropiate test is the t-test for two independent samples
D. 2 is the biggest number available there, so it would produce the narrowest graph.
From the image, we can see the amount of water in Liters are in the beaker.
The beaker is marked with numbers that are skip counting by 10. (10,20,30) so on. There are 4 ticks below the 10, 5 if you count the 10.
So that means 10/5 = 2 L per tick.
The water goes above the 30 mark and under the 40 mark, which means it's somewhere in the 30's.
Since each tick is 2 L, and the water goes to the third tick:
2L + 2L + 2L = 6L.
Add 6L to 30: 30+ 6L = 36L
Answer:
90$
Step-by-step explanation:
yeah he needs 90$ and he already has 54, so he only needs 36 left
In 6 weeks.
For this problem, you need to determine
the least common multiple of the numbers given which is 2, 3, and 6. You
can calculate the LCM of multiple numbers by pairs.
The LCM of 2 and 3 is 6 because 6 is the smallest possible number that can be evenly divided by both 2 and 3.
Now you need the LCM of 6 and 6. Which is also 6, because 6 is the smallest number that can be evenly divided by 6.
So the LCM of 2, 3, and 6 is 6. So in 6 weeks, Clea will once again
have a music less, attend dance class, and have a dental appointment,
all during the same week.