All categories

3 years ago

Prime number after 167, 118, 82, 57, 41,

Mathematics

1 answer:

Fiesta28 [93]3 years ago

8 0

The prime numbers after 167, 118, 82, 57, 41 are 37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

Prime numbers are numbers that are divisible by 1 and itself.

This are number greater than one with only two factors which are 1 and itself.

In other words, this number, when they are divided by another number other

than 1 or itself , one will get a remainder that is not zero.

Example of prime numbers are 2, 5, 7, 11, 13 etc.

The prime numbers after 167, 118, 82, 57, 41 are as follows:

37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

learn more about prime number here: brainly.com/question/26013414

You might be interested in

10(x+9)-x What is the answer to this

kupik [55]

10(x+9)-x

Distribute

10x+90-x
9x+90
There it depends what it is equal to

For example 10(x+9)=x

Or 10(x+9)-x=0

6 0

3 years ago

Read 2 more answers

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$

6 0

3 years ago

Which should I choose

maw [93]

Answer:

Now thats you've had time to think about it.

They rotate and then move down!
C

8 0

3 years ago

Read 2 more answers

Help me out with these points pleasee

Inessa [10]

Answer:

Step-by-step explanation:

heres the picture, with the points. hope this helped

4 0

3 years ago

What is 3 x (-4) x (-10) x (-8)

Elena L [17]

Assuming that those are not x's and they are multiplication signs, just use a calculator. If they are x's, the question is improper, and needs to be restated. Reply to this with the correct problem and I can answer it :3

6 0

3 years ago

Read 2 more answers