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hjlf
2 years ago
5

3x = 2y. Is this equation a linear or non-linear relation? How do you know?

Mathematics
1 answer:
viktelen [127]2 years ago
7 0

Answer:

  • linear equation
  • all variables are to the first power

Step-by-step explanation:

"Linear equation" is another way to say "first-degree equation." That is, the equation involves constants and variables to the first degree only. No term contains any product or ratio of variables.

A term is first degree when the sum of all of the exponents of the variables is 1, and all exponents are positive integers. That is, the only allowed exponent of the single variable in a term is 1.

Here, the term on the left side of the equal sign has x to the first power. The term on the right side of the equal sign has y to the first power. Both are linear terms, so this is a linear equation.

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A set of physics exam scores are normally distributed with a mean of 80 points and a standard deviation of 6
Anuta_ua [19.1K]

Answer:

The proportion of exam scores that are lower than Irina's score is 0.9938

Step-by-step explanation:

<u>Data</u>

  • mean: 80 points
  • standard deviation (sd): 6 points
  • value of interest (x): 95 points

z-score is computed as follows:

z = (x - mean)/sd

z = (95 - 80)/6 = 2.5

We want to find:

P(z < 2.5)

From the table attached:

P(z < 2.5) = 0.9938

3 0
3 years ago
AB = 2x-5 BC = 6x AC = 27
OlgaM077 [116]

Answer:

correct answer is x = 2.75

Step-by-step explanation:

Given;

AB = 2x-5

BC = 6x

AC = 27

Hence,

=> AC = AB + BC

=> 27 = 2x-5 + 6x

=> 27 = 8x-5

=> 27-5 = 8x

=> 22 = 8x

=> 22/8 = x

=> 11/4 = x

or

2.75 = x

3 0
2 years ago
What is 5 11/10 simplified
lbvjy [14]

Answer:

61/10 or in decimal form 6.1 or 6 1/10

Step-by-step explanation:

3 0
2 years ago
Help please<br>solve for Y​
Valentin [98]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which choice is equivalent to the product below?
Crank

Answer:

2√21

Step-by-step explanation:

1) Simplify.

√84

2) Simplify √84 to 2√21.

2√21

8 0
2 years ago
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