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3 years ago

Why does a siren have a higher pitch as it approaches you?

Mathematics

2 answers:

Airida [17]3 years ago

7 0

Answer:

Apparent Increase in Wave Frequency

As the ambulance approaches you, the distance between the source of the waves and the observer decreases. Consequently, the siren sounds more shrill as the pitch of the wailing siren 'sounds' higher than its original value, as sound waves reach you 'more frequently'.

Step-by-step explanation

hope this helps

Ainat [17]3 years ago

6 0

Answer: C. The crests of the sound wave are spaced closer together.

Step-by-step explanation:I took the test.

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Oliver drove the first 90 miles of his journey in 1.5 hours and the remaining 120 miles in 3 hours. What was the total average s

laila [671]

Answer:

46 2/3

Step-by-step explanation:

Divide 90 by 1.5 because:

Average Distance= distance/time

then 120 by 3 for same reason

then u find each

then add 90 with 120 to get 210 then divide by 4.5 to get 46 2/3

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3 years ago

Read 2 more answers

A tablet PC contains 3217 music files. The distribution of file size is highly skewed with many small files. Suppose the true me

m_a_m_a [10]

Answer:

Let X the random variable who represents the file sizeof music. We know the following info:

$\mu =2.3,\sigma =3.25$

We select a sample of n=50 nails. That represent the sample size.

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the file sizeof music. We know the following info:

$\mu =2.3,\sigma =3.25$

We select a sample of n=50 nails. That represent the sample size.

Since the sample size is large enough n >30, we can use the central limit theorem. From this theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we can approximate the distribution of the sample mean as a normal distribution and no matter if the distribution for X is right skewed or no.

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3 years ago

A watering can dispenses water at the rate of 0.25 gallon per minute. The original volume of water in the can was 6 gallons. Whi

Monica [59]

At x=0 y=6 the y intercept. The rate is -0.25 so the equation is y=6-0.25x. The ordered pair is (x,6-0.25x).

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3 years ago

How to find the volume of a rectangular prism

mr_godi [17]

Length times width times height

8 0

3 years ago

Read 2 more answers

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

==================================================

Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0

3 years ago