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3 years ago

How do you put nine thousand, nine hundred thirty nine in a number

Mathematics

2 answers:

yawa3891 [41]3 years ago

6 0

Answer:

9,939

Step-by-step explanation:

9,000 nine thousand

900 nine hundred

30 thirty

9 nine

mojhsa [17]3 years ago

5 0

Answer: The numerical form of that number is 9,939.

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The width of a triangle is six more than twice the height. The area of the triangle is 88in2. Find the height and base of the tr

malfutka [58]

For this case we have that by definition, the area of a triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It is the base of the triangle

h: It is the height of the triangle

According to the statement data we have:

$b = 6 + 2h$

Substituting we have:

$88 = \frac {(6 + 2h) * h} {2}\\176 = 6h + 2h ^ 2\\2h ^ 2 + 6h-176 = 0$

We divide between 2 on both sides:

$h ^ 2 + 3h-88 = 0$

We factor by looking for two numbers that, when multiplied, are obtained -88 and when added together, +3 is obtained.

These numbers are +11 and -8.

$(h + 11) (h-8) = 0$

We have two roots:

$h = -11\\h = 8$

We choose the positive value.

Thus, the base of the triangle is: $b = 6 + 2 (8) = 22$

Answer:

The base of the triangle is 22 units.

5 0

4 years ago

Read 2 more answers

HELP ME A rock garden is in the shape of a triangle as shown. Which equation could be used to find the area of the rock garden?

olga_2 [115]

I believe the answer would be the bottom left one

6 0

3 years ago

I need #2, #3, #4, #7, and #8. but do as much as you can pls thanks !

kifflom [539]

Answer:

See explanation.

Step-by-step explanation:

2) Your written answer is correct, y = x +4

3) Slope of perpendicular line: 5/2

y=mx+b

4 = (5/2)(4) + b

4 = 10 + b

b = -6

So, y=(5/2)x - 6

4) Slope of perpendicular line: 1

y=mx+b

5 = (1)(4) + b

5 = 4 + b

b = 1

So, y = x + 1

7) Slope of perpendicular line: 3/4

y=mx+b

4 = (3/4)(4) + b

4 = 3 + b

b = 1

So, y = (3/4)x + 1

8) Slope of perpendicular line: 1/4

y=mx+b

-2 = (1/4)(0) + b

b = -2

So, y = (1/4)x - 2

4 0

3 years ago

Find the points on the lemniscate where the tangent is horizontal. 8(x2 + y2)2 = 81(x2 − y2)

slamgirl [31]

The answers to this problem are:(±5√3/8,±5/8)Here is the solution:
Step 1: x2+y2=2516[2]x2+y2=2516[2]

Step 2: Substitute:
8(25/16)^2=25(x^2−y^2)
8(25/16)^2=25(x^2−y^2)
x^2−y^2=25/32.

Add [2] and [3]:
2x^2=75/32
x^2=75/74
x=±5√3/8
Substitute into [2]:
75/64+y^2=50/32
y^2=25/64
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4 years ago

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A ray that contains a point that is equidistant from both sides of the angle. *

seraphim [82]

Consider a angle â BAC and the point D on its defector Assume that DB is perpendicular to AB and DC is perpendicular to AC. Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC Proof Consider triangles Î”ADB and Î”ADC Both are right angle, â ABD= â ACD=90 degree They have congruent acute angle â BAD and â CAD( since AD is angle bisector) They share hypotenuse AD therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles

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4 years ago