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3 years ago

How do you put nine thousand, nine hundred thirty nine in a number

Mathematics

2 answers:

yawa3891 [41]3 years ago

6 0

Answer:

9,939

Step-by-step explanation:

9,000 nine thousand

900 nine hundred

30 thirty

9 nine

mojhsa [17]3 years ago

5 0

Answer: The numerical form of that number is 9,939.

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Combine the radicals 9✔x -3✔x

Anit [1.1K]

Answer:

6√x

Step-by-step explanation:

Given :-

9√x - 3√x .

For combining , take √x as common ,

=> √x ( 9 - 3 )

=> √x * 6

=> 6√x

7 0

3 years ago

What is 24% as a growth and decay factor

Lisa [10]

Answer:

When given a percentage of growth or decay, determined the growth/decay factor by adding or subtracting the percent, as a decimal, from 1. In general if r represents the growth or decay factor as a decimal then: b = 1 - r Decay Factor. b = 1 + r Growth Factor. A decay of 20% is a decay factor of 1 - 0.20 = 0.

Step-by-step explanation:

5 0

3 years ago

Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement

Furkat [3]

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(all students) - (M or S) = 150 - 80 = 70

8 0

3 years ago

In a sample of 115 115 curtains, the average length was found to be 32.2in. 32.2 ⁢ in. With a standard deviation of 0.8 0.8 . Gi

pentagon [3]

Answer:

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$s = 0.8, n = 115$

The point estimate for the population standard deviation of the length of the curtains is $\sigma$ . So

$s = \frac{\sigma}{\sqrt{n}}$

$\sigma = s\sqrt{n}$

$\sigma = 0.8\sqrt{115}$

$\sigma = 8.58$

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

3 0

3 years ago

A small boat traveled 29.5 miles upstream in 2 hours. The same boat took 3 hours to travel 59.25 miles downstream. If the speed

mel-nik [20]

Answer:

boat speed: 17.25 mph
current: 2.5 mph

Step-by-step explanation:

Upstream, the speed of the current (c) subtracts from the speed of the boat (b) to give the net speed. Downstream, the speed of the current adds. We can make use of the relation ...

speed = distance/time

b-c = 29.5/2 = 14.75 . . . . . miles/hour

b+c = 59.25/3 = 19.75 . . . .miles/hour

Subtracting the first equation from the second, we get ...

(b+c) -(b-c) = 19.75 -14.75

2c = 5

c = 2.5

Then either equation can be used to find b:

b = 14.75 +c = 17.25

The speed of the boat in still water is 17.25 miles per hour; the speed of the current is 2.5 miles per hour.

5 0

3 years ago