Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
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Step-by-step explanation:
i wanna know
math teacher said its associative
Approximately there are some of these on the we
Hey Katie
4^2x+3 = 1
We need to solve for x
log(4^2x+3) = log (1)
Now take log of
(2x +3) * log (4) = log (1)
2x + 3 = log(1)/log(4)
2x + 3 = 0
2x = 0 - 3
2x = -3
x = -3/2
I hope that's help !
