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ollegr [7]
3 years ago
13

Where should the lower quartile line be placed?

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0
Between the median and the number before it and everything in front of it is the lower quartile
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Two brothers have ages that are consecutive odd integers. The product of their ages is 38 less than the older brother's age squa
Lemur [1.5K]

answer = the elder bother is 17 and the younger one is 15

constructive odd integers= 15 and 17

17×15= 255

255+38 = 293

Square root of 293 = 17

5 0
3 years ago
Evaluate the expression for <br> x = 4, y=-2, z= -3.<br> 2² + 8zy - y²
andrew11 [14]

Answer:

Pretty sure its 53

Step-by-step explanation:

9+48-4

3 0
3 years ago
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PLEASE HELP! I NEED TO GET THIS DONE SOON!
tensa zangetsu [6.8K]

Answer:6

Step-by-step explanation:

In a circle, a radius perpendicular to a chord bisects the chord. So BC = CA BC = 6 (given) x (or AC) = 6 Answer = 6. Tell me if I was right. Thanks.

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A track team will run a 4 mile relay race. The coach divided the students into groups of 4. The first runner of each group would
natita [175]
If a track team is running a relay race, shouldnt they be running the same distance? The fourth person who runs is going to be running alot more than everyone else. 
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3 years ago
Six​ stand-up comics,​ A, B,​ C, D,​ E, and​ F, are to perform on a single evening at a comedy club. The order of performance is
kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

P(F=4th)=1/6

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

P(F, D, B, A, C, E)=1/720

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

P(C=6th\,or\, E=6th)=2/6=1/3

8 0
3 years ago
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