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egoroff_w [7]
3 years ago
5

Simplify. write the expression using only postive exponents. m^-4*n^3

Mathematics
1 answer:
inna [77]3 years ago
5 0

\frac{ {n}^{3} }{  {m}^{4}  }
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Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.
Ann [662]

Given:

Consider the given function is:

f(x)=x^2-8x+13

To find:

The average rate of change of the function over the interval -1\leq x\leq 6.

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

We have,

f(x)=x^2-8x+13

At x=-1,

f(-1)=(-1)^2-8(-1)+13

f(-1)=1+8+13

f(-1)=22

At x=6,

f(6)=(6)^2-8(6)+13

f(6)=36-48+13

f(6)=1

Now, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is:

m=\dfrac{f(6)-f(-1)}{6-(-1)}

m=\dfrac{1-22}{7}

m=\dfrac{-21}{7}

m=-3

Therefore, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is -3.

6 0
2 years ago
Can someone pls help me on the last three!
Solnce55 [7]
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4 0
3 years ago
Find the product.<br><br> (-5a ^2)^3·a ^5<br><br> A)-15a10<br> B)-125a11<br> C)15a6<br> D)-125a10
Ber [7]

Answer:

  B)  -125a^11

Step-by-step explanation:

(-5a^2)^3·a^5 = (-5)^3·a^6·a^5

  = (-5)^3·a^(2·3)·a^5

  = (-5)^3·a^6·a^5

  = -125·a^(6+5)

  = -125·a^11 . . . . matches choice B

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

5 0
2 years ago
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What is the hundreth place in decmials
igor_vitrenko [27]
The 2nd place after(to the right) the decimal. For example: .01. 1 would be in the hundredth place.
6 0
3 years ago
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draw a rectangle on the grid by plotting the points (-3, -2) (-3,3) (6,-2) and(6,3) please help this is for my packet
guapka [62]
Just look for the coordinates left ones are along x axis and right are on y axis

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