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Otrada [13]
4 years ago
12

Anthony got a new iPhone. He needs to create a 4-digit passcode. How many passcodes can be created if REPETITION OF DIGITS IS AL

LOWED? Please show your work.
Mathematics
1 answer:
Snezhnost [94]4 years ago
7 0
An infinite amount...since there ARE and infinite amount of number in the universe.

1111

2222

3333

4444

5555

6666

7777

8888

9999


1010

1234

4321

5432

2345

5678

8765

0987

7890

4509

9054

Etc
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HELP PLEASE NEED THIS DONE
givi [52]

Answer:

Step-by-step explanation:

A

4 0
3 years ago
Read 2 more answers
A state park charges an entrance fee based on the number of people in a vehicle. A car containing 2 people is charged $14, a car
Artyom0805 [142]

Answer:

Therefore $98 is be charged a bus containing 30 people.

Step-by-step explanation:

Given that,

A state park charges an entrance fee based on the number of people in vehicle.

Let the entry fee for the vehicle be E and entry fee for each person be x.

Then

C= E+(P×x)

C= Total charge in $

E= entry fee for a vehicle

P=No. of person

x= Entry charge per person.

Given A car containing 2 people charged $14

C=$14, P=2

∴14= E+(2× x)

⇒E+2x=14.....(1)

Again A car containing 4 people charged $20

C=$20, P=4

∴20= E+(4× x)

⇒E+4x=20.....(2)

Subtract (1) from (2), we get

E+4x-(E+2x)= 20-14

⇒E+4x-E-2x=6

⇒2x=6

⇒x=3

Putting the value of x in equation (1)

E+(2×3)=14

⇒E=14-6

⇒E=8

Therefore E=$8 and x=$3

Next we check whether our assumption is correct or wrong. Putting the value of E and x for third case

Here P= 8

Therefore C= E+(P×x)

                    = 8+(8× 3)

                    =8+24

                   =$32

Therefore our assumption is correct.

Now C=? , P= 30

The charged for the 30 people is

C= $[8+(30×3)]

  =$[8+90]

 =$98

Therefore $98 is be charged a bus containing 30 people.

4 0
3 years ago
Suppose that
Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

csc(B) = 13/12

sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12

The six  trigonometric functions of angle B are:

sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\

7 0
4 years ago
I need the step by step answer for 1/3(9x+3)=3x+1
Natalka [10]
1/3 * 9x = 3x

1/3 * 3 = 1

3x + 1 = 4x

3x + 1 = 4x

4x=4x
7 0
3 years ago
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Jeanna is making holiday cupcakes for her family. She typically makes 2 dozen red velvet and 3 dozen gingerbread spice cake. Sin
valentina_108 [34]

Answer:

15 dozens of cakes

Step-by-step explanation:

It is given that Jeanna is making cupcakes for her family and she normally makes 2 dozens of red velvet cakes and 3 dozens of gingerbread spice cakes. But as everybody is staying at home, Jeanna wants to increase the standard amount by 3 for enough cakes.

So,

2 dozens of velvet cakes, i.e.

2 x 12 = 24 red velvet cakes

Increasing this amount by 3 times will give us 24 x 3 = 72 red velvet cakes.

Similarly,

3 dozens of gingerbread spice cakes, i.e.

3 x 12 = 36 gingerbread spice cakes

Increasing this amount by 3 times will give us 36 x 3 = 108 gingerbread spice cakes.

Therefore the total number of cakes is = 72 + 108

                                                                 = 180 cakes.

We know 1 dozen = 12

Therefore dividing 180 cakes by 12, we get

$=\frac{180}{12}$

= 15 dozen cakes.

Therefore, now Jeanna will have to make 15 dozens of cupcakes for all.

5 0
3 years ago
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