There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
At Gino's you pay $16 plus $8 per pizza.
At Venetian's you pay $24 plus $6 per pizza.
Let the number of pizzas be x.
At Gino's you pay 16 + 8x
At Venetian's you pay 24 + 6x
Set the two costs equal and solve for x to find out the number of pizzas for which both costs are the same.
16 + 8x = 24 + 6x
16 + 2x = 24
2x = 8
x = 4
Each place gives you a free pizza.
4 pizzas plus the free pizza equals 5 pizzas.
If you need 5 pizzas (including the free one), both parlors cost the same.
If you need fewer than 5 pizzas, use Gino's.
If you need more than 5 pizzas, use Venetian's.
Answer:
Look at my explanation
Step-by-step explanation:
The circumference of a circle is 2πr, so you can set it up like this since the circumference was 22π.
2πr = 22π
divide both sides by 2
πr = 11π
divide both sides by π
you get r = 11
So your radius is 11.
To find the area, you must do πr^2 ("^2" means squared)
if you substitute 11 for r you get
11π^2
you can do 11 squared first
11^2 = 121
the area of the circle = 121π
Keep in mind that they said to use 3.14 for π
so you can do 121 x 3.14
Final Answer: 379.94
Answer:
Click the third one, I hope I helped, and have a good day :)
6÷2=3. or 9÷3=3 or 18÷6=3
