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2 years ago

7

Prove that these two triangles are congruent.

1 answer:

fredd [130]2 years ago

6 0

Answer:

thank for the pointshhhhfgtf5ttctctx4dd5y8hhousjshs

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9. What coordinates will a point (x, y) reflected over the x-axis have?

Charra [1.4K]

The answer to your question is c

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2 years ago

I’m really bad at math can someone help me?(this is due today!)

dangina [55]

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2 years ago

THE DIMENSIONS OF A CUBED ARE 4X C.M,6X C.M AND 10X C.M

scZoUnD [109]

Answer:

A. 248 square CM

B. 240 cubic CM

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2 years ago

The difference between number 20 and its opposite is what percentage of 200? (if you do not remember: opposite of 15 is −15; opp

True [87]

20%

This is because 20 and it's opposite -20 is 40. (20 - -20 = 40). Then 40 is 20% of 200.

8 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago