4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5
2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
I hope this makes sense to you.
95% = 95/100
95/100 of 76/1. (Always remember that every whole number is over 1)
So now we have 95/100 of 76/1
We can't solve with "of"
So we'll have to change it to "times(x)".....when we do that, it would cause 76/1 to reciprocate to 1/76
So now we have this: 95/100 x 1/76
When we solve it this is what we'll get: 19/20 x 1/76 = 19/1520 = 1/80
The value of
is -80
<h3><u>Solution:</u></h3>
Given that x y is a real number
Also given that ![x \times y = x(x - y)](https://tex.z-dn.net/?f=x%20%5Ctimes%20y%20%3D%20x%28x%20-%20y%29)
We are asked to find the value of ![2 \times (7 \times 1)](https://tex.z-dn.net/?f=2%20%5Ctimes%20%287%20%5Ctimes%201%29)
To solve it we have to first solve terms in brackets.
![\begin{array}{l}{\text {So, } 7 \times 1=7(7-1) \quad[\text {from given rule }]} \\\\ {\rightarrow 7 \times 1=7 \times 6} \\\\ {\rightarrow 7 \times 1=42} \\\\ {\text {Now, the required expression is modified as } 2 \times 42} \\\\ {\text {Then, } 2 \times 42=2(2-42)=2(-40)=-80} \\\\ {\text {Hence, the value of } 2 \times(7 \times 1)=-80}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7BSo%2C%20%7D%207%20%5Ctimes%201%3D7%287-1%29%20%5Cquad%5B%5Ctext%20%7Bfrom%20given%20rule%20%7D%5D%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%207%20%5Ctimes%201%3D7%20%5Ctimes%206%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%207%20%5Ctimes%201%3D42%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BNow%2C%20the%20required%20expression%20is%20modified%20as%20%7D%202%20%5Ctimes%2042%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BThen%2C%20%7D%202%20%5Ctimes%2042%3D2%282-42%29%3D2%28-40%29%3D-80%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BHence%2C%20the%20value%20of%20%7D%202%20%5Ctimes%287%20%5Ctimes%201%29%3D-80%7D%5Cend%7Barray%7D)
The unit price would be $8.
48/6 = 8
Answer:
-1.83337261989
Step-by-step explanation:
(2 1/3)/y=-1.272727
2 1/3 = -1.272727y
y=-1.83337261989