Answer:
Given
Edge of a cube = 10cm
Length, l = 12.5 cm
Breadth, b = 10cm
Height, h = 8 cm
Find out
We have to find
i) Which box has the greater lateral surface area and by how much?
ii) Which box has the smaller total surface area and by how much?
Solution
(i)
Lateral surface area of a cube = 4 * (edge)2
= 4 * 102 cm2
= 400 cm2
Lateral surface area of a cuboid = 2 (lh + bh)
= 2 (12.5 * 8 + 10 * 8) cm2
= 2 (100 + 80) cm2
= 360 cm2
So, the lateral surface area of the cubical box is greater than cuboidal box by (400 cm2 – 360 cm2) which is 40 cm2.
(ii)
Total surface area of a cube = 6 * (edge)2
= 6 * 102 cm2
= 600 cm2
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (12.5 * 10 + 10 * 8 + 12.5 * 8) cm2
= 2 (125 + 80 + 100) cm2
= 610 cm2
Therefore, the total surface area of the cuboidal box is greater than the cubical box by (610 cm2 – 600 cm2) which is 10 cm2.
Answer:
Without an opposite, the only operation that can be used is C a/h or Cos Adjacent/ Hypotenuse
Answer:
Since there are 2 sides, a front & back, and a top & bottom, you must find the surface area of each of those 3 surfaces and multiply by 2.
Step-by-step explanation:
The formula would be:
Top & Bottom - 5 × 4 (multiply by 2 for top AND bottom)
Front & Back - 5 × 7 (multiply by 2 for front AND back)
Sides - 4 × 7 (multiply by 2 for BOTH sides)
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Once you find the 3 surface areas, add the areas all together for the total. (I did not show the answer because that is for you to do on your own.)
Ex. Top & Bottom + Front & Back + Sides
Answer:
9/4
Step-by-step explanation:
