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jolli1 [7]
4 years ago
14

The long side of a box is 6 inches. That is 3 times the length of the short side. How long is the short side? PLEASE HELP NEED A

SAP.....THANK YOU.
______inches.
Mathematics
2 answers:
Montano1993 [528]4 years ago
5 0

Answer:

2 inches

Step-by-step explanation:

If the long side is 6 inches and it's 3x the length of the short side, then you need to divide the long side into 3 parts because the short side is 1/3 the length of the long side. This means that the short side is 2 inches.

DerKrebs [107]4 years ago
4 0

Answer:

Short side is 2 inches

I hope that helps. :)

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In-s [12.5K]

Answer:

18

Step-by-step explanation:

y  = mx + b

m = slope

b = y-intercept

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3 years ago
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Below is an Algebraic Proof that shows how the expression x(1+y) + y(2+x) is equivalent to x + 2xy + 2y. Some of the steps are l
harina [27]

Answer:

Step-by-step explanation:

          Steps                                     Property

x(1 + y) + y(2 + x)                           Given

x + xy + 2y + xy                            Distributive property

x + xy + xy + 2y                            Commutative property of addition

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x + (xy + xy) + 2y                           Associative property of addition

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x + 2xy + 2y                                  Combine like terms

5 0
3 years ago
Suppose I pick a jelly bean at random from a box containing two red and ten blue ones. I record the color and put the jelly bean
Lubov Fominskaja [6]

Answer:

The probability of getting a red jelly bean both of the times is 0.028.

Step-by-step explanation:

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ProbabilityRed=\frac{1}{12} +\frac{1}{12}=\frac{2}{12}

Now we can calculate the probability of getting the red jelly bean twice, this will be the product of the probability of getting each one, is the same probability for the second chance because we are getting the jelly bean back in the box, this is:

ProbabilityBothRed=\frac{2}{12} *\frac{2}{12}=\frac{4}{144}  =\frac{1}{36} =0.028

Now we have that the probability of getting a red jelly bean both of the times is 0.028.

6 0
4 years ago
Write an e-mail (50-60 words) to one of your friends to ask him/her for some advice on improving your English speaking skill. Wr
Bingel [31]

Writing an email to a friend asking for help regarding English speaking skills.

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3 0
3 years ago
Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
3 years ago
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