The area of a circle with radius of 13 millimeters is A≈530.93A=πr2=π·132≈530.92916
Any answer less than one would work, soothe answers are A and D
f
'
(
x
)
=
1
(
x
+
1
)
2
Explanation:
differentiating from first principles
f
'
(
x
)
=
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
f
'
(
x
)
=
lim
h
→
0
x
+
h
x
+
h
+
1
−
x
x
+
1
h
the aim now is to eliminate h from the denominator
f
'
(
x
)
=
lim
h
=0
(
x
+
h
)
(
x
+
1
)−
x
(
x
+
h
+
1)
h
(
x
+
1
)
(
x
+
h
+
1
)
f
'
(
x
)
=
lim
h
→
0
x
2
+
h
x
+
x
+
h
−
x
2
−
h
x
−
x
h
(
x
+
1
)
(
x+h
+
1
)
f
'
(
x
)
=
lim
h
→
0
h
1
h
1
(
x
+
1
)
(
x
+
h
+1
)
f
'
(
x
)
=
1
(
x
+
1
)
2
Hi :)
x = 1/2n
Subtract 17nx from both sides
9−nx−17nx = 0
Combine −nx and −17nx to get −18nx
9 −18nx = 0
Subtract 9 from both sides
−18nx = −9
The equation is in standard form
(−18n)x=−9
Divide both sides by −18n
(-18n)x/ -18n = -9/ -18n
Dividing by −18n undoes the multiplication by −18n
x= -9/ -18n
Divide −9 by −18n
x= 1/2n
Hope this helps :)
so... that's how much an internal angle is
now, subtract that from 180 and you get the angle outside, in the picture
subtract that outside angle twice from 180, and you get angle "2"
because angle 2 is in the same triangle as those two outside angles, and all internal angles in a triangle is 180, thus 180 - (those two angles) is angle "2"
