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Nadusha1986 [10]
3 years ago
6

The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller

polygon is 12 sq. units. What is the area of the larger polygon?
Mathematics
1 answer:
Softa [21]3 years ago
4 0
You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think. 


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3 years ago
Three functions are given below: f(x), g(x), and h(x).
Rzqust [24]

Answer: The axis of symmetry is x=1.

Explanation:

The given function is,

g(x)=5x^2-10x+7

The degree of the equation is 2.  SInce it is a quadratic function therefore the graph of the function is a parabola.

The axis of symmetry of a parabolic function f(x)=ax^2+bx+c is a vertical line,

x=-\frac{b}{2a}

Since the value of a is 5m b is -10 and c is 7, So the axis of symmetry is,

x=-\frac{(-10)}{2(5)}

x=\frac{10}{10}

x=1

Therefore, the axis of symmetry is x=1.

5 0
3 years ago
A circle with area 9pi has a sector with a central angle of 1/9pi radians. What is the area of a sector? Either enter an exact a
sveta [45]

Answer:

Step-by-step explanation:

5 0
4 years ago
Could someone explain how to do this, I have no idea how...
alexira [117]

Answer:

2a²

Step-by-step explanation:

Pair 'like' terms with 'like' terms, ie numbers go with numbers, and 'a's go with 'a's.

Lets deal with the top of the fraction first:

4ax3a³

Rearrange it so you have numbers beside numbers and 'a's beside 'a's:

(4x3)x(axa³)

12x(a⁴) <em>(because nᵃxnᵇ=nᵃ⁺ᵇ)</em>

12a⁴

Now, instead of (4ax3a³)/6a², we have 12a⁴/6a²

First divide the numbers: 12/6 =2

Now divide the 'a' parts: a⁴/a²=a² <em>(because nᵃ/nᵇ=nᵃ⁻ᵇ)</em>

Now we have 2a²

7 0
3 years ago
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