Answer:
<u>∠IJG = 123° </u>
Step-by-step explanation:
Since AB║CD, EF ║GH, we can use the Corresponding Angles Postulate, for finding the following congruent angles:
∠IKL ≅ ∠EIJ and ∠EIJ ≅ ∠GJA
∠GJA and ∠IJG are supplementary, therefore:
∠GJA + ∠IJG = 180°
∠IJG = 180° - 57°
<u>∠IJG = 123°</u>
Hmmm if you don't have a Unit Circle, this is a good time to get one, many you can find online. Anyhow, check your unit circle for cos(30°) and sin(30°).
Yes the first choice is the right choice.
Remember that the 3rd root range is from -infinity to infinity.
<h3>
Answer: Q = 8</h3>
====================================================
Explanation:
The left hand side of the first equation is x-3y
The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y
If we multiply both sides of the first equation by 2, we get
x-3y = 4
2(x-3y) = 2*4
2x-6y = 8
Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.
We can say each solution is in the set {(x,y): x-3y = 4}
Which is the same as saying each solution is of the form (3y+4,y)
