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denis23 [38]
3 years ago
11

Can I please get help with this question please?

Mathematics
2 answers:
solmaris [256]3 years ago
6 0

what are the choices?


babunello [35]3 years ago
3 0
What are the choices
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This graph displays a linear function. What is the rate of change?
ivolga24 [154]

Answer:

5/1 or 5

Step-by-step explanation: You find two points that the line goes on. So in this it would be 1,1 for the first one, the second one is 2,4. Then you go from the first point up or down to get to the same level at the second point. Then you go over to the left or right to meet the second point, in this graph you will go up 5 times to get to the same level. Then over 1 time to get to the point. Then you divide the rise over the run the rise is 5 and the run is 1, so you would do 5 divided by 1 and the answer of that is 5.

Hope this helps you in the future

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3 years ago
Need help solving this problem
dimulka [17.4K]

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Step-by-step explanation:

4 0
3 years ago
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An example of Power of a Power Property
ella [17]
Power of a power as applied to exponents is the following:

The power of a power is the product of the exponents, or

(x^a)^b = x^(ab)

For example
(5^2)^3=5^(2*3)=5^6=15625
3 0
3 years ago
Team tool bella canoed 15 3/4 miles in 5/4 hours. What was their average rate of speed in mph ​
luda_lava [24]

Average speed is 12.6 miles per hour

<em><u>Solution:</u></em>

Given that team tool bella canoed 15\frac{3}{4} miles in \frac{5}{4} hours

To find: average rate of speed in miles per hour

From given information,

distance = 15\frac{3}{4} \text{ miles } = \frac{15 \times 4+3}{4} = \frac{63}{4} \text{ miles}

time = \frac{5}{4} \text{ hours}

To find the speed we use the below formula,

speed = \frac{distance}{time}

Substituting the given values we get,

speed = \frac{\frac{63}{4}}{\frac{5}{4}}\\\\speed = \frac{63}{4} \times \frac{4}{5} = \frac{63}{5} = 12.6

Thus average speed is 12.6 miles per hour

7 0
3 years ago
Absolute value inequality
Marizza181 [45]

|x| because just Google it if I'm wrong

8 0
3 years ago
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