All categories

4 years ago

35,000 decreases by 22%

Mathematics

2 answers:

Klio2033 [76]4 years ago

5 0

Answer:

27300

Step-by-step explanation:

100%-22% = 78%

.78 * 35000 = 27300

Nookie1986 [14]4 years ago

3 0

Answer:

27,300

Step-by-step explanation:

New value =

35,000 - Percentage decrease =

35,000 - (22% × 35,000) =

35,000 - 22% × 35,000 =

(1 - 22%) × 35,000 =

(100% - 22%) × 35,000 =

78% × 35,000 =

78 ÷ 100 × 35,000 =

78 × 35,000 ÷ 100 =

2,730,000 ÷ 100 =

27,300

You might be interested in

If cosA=2/5, find the value of 4+4 tan^2A

Andrew [12]

The first equation is given to determine A.

cos A = 2/5
A = cos⁻¹(2/5) = 66.42°

Now that we know A, we use this value to the second equation.

4 + 4tan²A = 4 +24.996 4tan²(66.42°) = 24.996 ≈ 25

7 0

3 years ago

I'd appreciate someones help right about now Haha :) I need help :/

My name is Ann [436]

The mean is 6 because you have to add all the numbers and divide by 5

3 0

3 years ago

Read 2 more answers

Richard wants to purchase a Jeep. The purchase price of the Jeep is $ 42 , 000. The dealership will allow him to pay cash or fin

laiz [17]

It will take him around 56 months to finish off his payment if he puts a down payment of 4,000 and pays $680 a month

7 0

2 years ago

Humpty Dumpty was taken to the hospital. His bill was $4530. His insurance covered 70% of his claim and he had to pay an emergen

Nana76 [90]

In 12 months he pays $113.35 per month plus the $70

6 0

3 years ago

Of 200 youthful gamers (under 18) who tried the new Z-Box-Plus game, 160 rated it "excellent," compared with only 144 of 200 adu

beks73 [17]

Answer:

Correct option is (c). 1.873.

Step-by-step explanation:

The hypothesis can be defined as:

H₀: There is no difference between the two proportions.

Hₐ: There is a difference between the two proportions.

Given:

$X_{1} = 160,\ n_{1}=200\\X_{2} = 144,\ n_{2}=200$

The sample proportion of youthful gamers who tried the new Z-Box-Plus game and rated it "excellent," is:

$\hat p_{1}=\frac{X_{1}}{n_{1}} =\frac{160}{200} =0.80$

The sample proportion of adult gamers who tried the new Z-Box-Plus game and rated it "excellent," is:

$\hat p_{2}=\frac{X_{2}}{n_{2}} =\frac{144}{200} =0.72$

The population proportion of gamers who rated the game as "excellent" is:

$P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}} =\frac{160+144}{200+200}= 0.76$

The test statistic is:

$z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{P(1-P)[\frac{1}{n_{1}}+\frac{1}{n_{2}} ]} } =\frac{0.80-0.72}{\sqrt{0.76(1-0.76)[\frac{1}{200}+\frac{1}{200} ]} }=1.873$

Thus, the value of the test statistic is 1.873.

The correct option is (c).

5 0

3 years ago