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3 years ago

Please help with this

Mathematics

2 answers:

sergiy2304 [10]3 years ago

8 0

Is this for edgenuity? :/ cuz i have a teacher login.

adell [148]3 years ago

8 0

Triangle: 180 and so... yea

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Write an equation for the line that has a slope -8/9 and goes through the point (-7, 7)

Jobisdone [24]

Answer:

y = (-8/9)x + 0.77777

Step-by-step explanation:

We already know the slope, so the only thing left to find is the y-intercept.

To find the y-intercept, we can plug in the slope and point to the slope-intercept form equation (y = mx+b, where m=slope and b=y-int.)

y = m * x + b

(7) = (-8/9)*(-7) + b

Now, just solve for b!

(7) = (-8/9)*(-7) + b

7 = 56/9 + b

7 - (56/9) = b

b = 0.777777 (repeating decimal, usually signified by a little line above the 7)

so now we just plug in the slope and y-intercept we found into y = mx + b.

y = mx + b

y = (-8/9)x + 0.77777

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2 years ago

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How do you find 10% of 9900

Serhud [2]

Step-by-step explanation:

$10\% \: of \: 9900 \\ \\ = \frac{10}{100} \times 9900 \\ \\ = 10 \times 99 \\ \\ = 990$

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3 years ago

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A dog that weighs 14 pounds should eat 1 5/8 cups of a certain type of dog food per day. How much of the same type of dog food s

stira [4]

1 5/8 = 13/8
(13/8)/14 = .116 or 13/112
.116 (26) = 3.016 or 169/56

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3 years ago

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Is 2y-4=10 a function

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2 years ago

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Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a

Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

X = a person has the disease

P = the test result is positive

N = the test result is negative

Given:

$P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10$

Compute the value of P (P|X) as follows:

$P(P|X)=1-P(P|X^{c})=1-0.15=0.85$

Compute the probability of a positive test result as follows:

$P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22$

Compute the probability of a person having the disease given that he/she was tested positive as follows:

$P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864$

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

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2 years ago