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ser-zykov [4K]
3 years ago
13

Some have argued that throwing darts at the stock pages to decide which companies to invest in could be a successful​ stock-pick

ing strategy. Suppose a researcher decides to test this theory and randomly chooses 250 companies to invest in. After 1​ year, 135 of the companies were considered​ winners; that​ is, they outperformed other companies in the same investment class. To assess whether the​ dart-picking strategy resulted in a majority of​ winners, the researcher tested Upper H 0​: pequals0.5 versus Upper H 1​: pgreater than0.5 and obtained a​ P-value of 0.1030. Explain what this​ P-value means and write a conclusion for the researcher.​
Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

<em>The calculated value Z = 1.2903 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted at 0.05 level of significance</em>

<em>The population proportion is equal to 0.5</em>

Step-by-step explanation:

<u><em>Step (i)</em></u>:-

Given random sample size ' n' = 250

Sample proportion 'p'

                                p= \frac{x}{n} = \frac{135}{250} = 0.54

Given Population proportion  P = 0.5

                                       Q = 1-P = 1-0.5 =0.5

<em>Null Hypothesis : H₀ </em>: P = 0.5

<em>Alternative Hypothesis : H₁</em> : P≥ 0.5

<u><em>Step(ii)</em></u>:-

<em>Test statistic </em>

               Z = \frac{p - P}{\sqrt{\frac{PQ}{n} } }

             Z = \frac{0.54-0.5}{\sqrt{\frac{0.5 X 0.5}{250} } }

       <em>     Z  = 1.2903</em>

<em>Level of significance α = 0.05</em>

<em>Z₀.₀₅ = 1.96</em>

<em>The calculated value Z = 1.2903 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted at 0.05 level of significance</em>

<u><em>Step(iii):</em></u><em>-</em>

<u><em>P- value</em></u>

<u><em>The probability of test statistic</em></u>

P(Z > 1.2903) = 0.5 - A ( 1.2903)

                      = 0.5 - 0.4015

                      = 0.0985≅ 0.10

i) <em>P- value =0.10 >  α = 0.05 </em>

<em> null hypothesis is accepted </em>

<u><em>Conclusion</em></u><em>:-</em>

<em>The population proportion is equal to 0.5</em>

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A devastating freeze in California’s Central Valley in January 2007 wiped out approximately 75% of the state’s citrus crop. It t
inna [77]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

  • <em>The linear equation of the function is: </em>g(P) =22.9P +7<em>, while its inverse is: </em>g^{-1}(c) = \frac{c - 7}{22.9}<em>.</em>
  • <em>The domain is from 0% to 100%, while the range is from 7 to 29.9</em>

<em />

Given that:

c = g(P)

<u>Input and Output quantity</u>

The input quantity is the <em>percentage of frozen citrus crop</em>, while the output quantity is the <em>cost of box of oranges</em>

<u>Linear Function</u>

The given parameters can be written as:

(P_1,c_1) = (20\%, 11.58)

(P_2,c_2) = (80\%, 25.32)

Calculate the slope (m)

m = \frac{c_2 - c_1}{P_2 - P_1}

So, we have:

m = \frac{25.32 - 11.58}{80\% - 20\%}

m = \frac{13.74}{60\%}

m = 22.9

The equation is then calculated using:

c =m(P - p_1)  + c_1

So, we have:

c =22.9(P - 20\%)  + 11.58

c =22.9P - 4.58  + 11.58

c =22.9P +7

So, the function is:

g(P) =22.9P +7

<u>The domain and the range</u>

The domain is the <em>possible input value (i.e. possible values of P).</em>

Because P is a percentage, its possible values are 0% to 100%.

Hence, the domain of the function is: [0\%,100\%]

The range is the <em>possible output value (i.e. possible values of c).</em>

When P = 0% and 100%

c = 22.9 \times 0\% + 7 = 7

c = 22.9 \times 100\% + 7 = 29.9

Hence, the range of the function is: [7,29.9]

<u>The meaning of </u>g^{-1}(12)<u />

g^{-1}(12) is an inverse equation, where 12 represents the <em>cost of box of oranges.</em>

So, g^{-1}(12) represents the percentage of frozen citrus crop, when the cost is $12.

<u>The inverse formula</u>

We have:

c =22.9P +7

Make P the subject

22.9P = c - 7

Divide by 22.9

P = \frac{c - 7}{22.9}

So, the inverse function is:

g^{-1}(c) = \frac{c - 7}{22.9}

<em>This is used to calculate the percentage of frozen citrus crop, when the cost is known.</em>

<em />

g^{-1}(c) = \frac{c - 7}{22.9}

Substitute 12 for c

g^{-1}(12) = \frac{12 - 7}{22.9}

g^{-1}(12) = \frac{5}{22.9}

g^{-1}(12) = 22\%

Read more about linear equations at:

brainly.com/question/19770987

4 0
3 years ago
What is the sum of 7/9 + 2/5
Marizza181 [45]
9/14 because 7+2 is 9 and 5+9 is 14
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4 years ago
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Peanuts are sold in 8-ounce and 12-ounce packages.
allsm [11]

Answer:

C) 24

Step-by-step explanation:

8; 16 24 32 40 48

12; 24 36 48 69 72

They both have the common multiple of 24 and 48 in the intermediate multiplication since 24 is half of 48 and is the smallest multiple that is the answer.

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2 years ago
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tickets originally worth p dollars were discounted by 28%. which expression represents the discounted price of the tickets?
castortr0y [4]

Answer:

.72p

Step-by-step explanation:

1p equals the original price

100 percent of p

we are reducing it by 28 percent, which means only 72 percent of p will remain

72 percent or .72

.72p

8 0
2 years ago
Please help! I've already answered part a, I don't understand what part b is asking.
Luba_88 [7]

Step-by-step explanation:

So, there is something known as a removable discontinuity, and it's essentially where you can define f(x) using the most simplified fraction, where you could normally not define f(x).

So we have the following equation:

f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}

As you may know, we cannot divide a number by the value of zero. When the denominator is equal to zero, on the graph this will appear as a vertical asymptote, where x approaches the value that makes the denominator zero, but never actually reaches it.

If you look at each denominator, you can set them equal to zero to find the vertical asymptotes

x+1 = 0

x=-1

There should be a vertical asymptote at x=-1, since it would make two of the denominators equal to -1, but let's divide the two fractions first.

Original Equation

f(x) = (\frac{x+5}{x+1}\div\frac{(x+3)(x-2)}{(x-4)(x+1)})-\frac{1}{x-2}

Keep, change, flip

f(x) = (\frac{x+5}{x+1}*\frac{(x-4)(x+1)}{(x+3)(x-2)})-\frac{1}{x-2}

Multiply the two fractions

f(x) = (\frac{(x+5)(x-4)(x+1)}{(x+1)(x+3)(x-2)})-\frac{1}{x-2}

Notice how the x+1 is in the numerator and fraction? That means we can cancel it out!

f(x) = (\frac{(x+5)(x-4)}{(x+3)(x-2)})-\frac{1}{x-2}

In this simplified version of the fraction, we can technically define f(-1), but in the original version, since it's not defined there is a removable discontinuity at x=-1, meaning there is no vertical asymptote, but the function is still not defined at f(-1), and there will be a hole at that point.

4 0
2 years ago
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