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3 years ago

PLEASE HELP ASAP!!!!!The graph below shows the solution set to which inequality?

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

Filled in circle means it must be an "...or equal to"

It's on 0, so must be an "...or equal to 0".

The arrow is going towards values bigger than zero, so it's "greater than or equal to 0"

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The graph shows the cost of buying tickets to a concert.

-Dominant- [34]

Answer:

305

Step-by-step explanation:

if the unit rate is $30.5 then thats how much it cost per 1 ticket.

To get 10 tickets we have to do x10

30.5 x 10 = 305

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2 years ago

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13/4% as fraction and decimal

nexus9112 [7]

Decimal: 3.25

Fraction: 13/4

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3 years ago

Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents. Her response was (8 x 10 to the po

Gnom [1K]

Kriste respone is wrong

Solution:

Given that,

Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents

Her response was (8 x 10 to the power of 3) x 5 to the power of 2

No, the response of Kristen is wrong

Let us first understand about exponents

An exponent refers to the number of times a number is multiplied by itself

Given expression is:

$80000 \times 25$

Here, 80000 has 4 zeros

Therefore, it can be raised as 10 power 4

$80000 = 8 \times 10^4$

Thus the expression becomes:

$80000 \times 25 = 8 \times 10^4 \times 25$

Also, 25 can be written as 5 power 2

$80000 \times 25 = 8 \times 10^4 \times 5^2$

Thus given expression is written as (8 x 10 to the power 4) x 5 power to the power 2

Thus Kristen respone is wrong, because he has raised 10 to power 3

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2 years ago

What is the measure of angle ONP?

olganol [36]

The answer is actually 80 degrees, I just took the test.

8 0

3 years ago

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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

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3 years ago

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