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Fiesta28 [93]
3 years ago
13

A salesman at a clothing store makes a sale to 30% of the customers he talks to, and wants to try out a new tecnique to see if h

e can change this rate. He decides to collect data for a few months on the percentage of customers he makes a sale to, and he is able to construct a 95% confidence interval of (.3095, .3275). Is there evidence at 5% significance that he has changed his average sales?
Mathematics
1 answer:
Alexus [3.1K]3 years ago
7 0

Answer:

Yes, we can conclude that average sales has changed.

Step-by-step explanation:

The null hypothesis, H0 : μ = 0.3

The alternative ; H0 : μ ≠ 0.3

The result of the 95% confidence interval of (.3095, .3275); This shows that the confidence interval is now between 30.95% and 32.75% ; since μ does not lie within the confidence interval value and the lower boundary of the confidence interval is > 30; we Can conclude with an evidence of 5% significance that his average sales as changed (increased).

We can reject H0 and conclude that μ > 0.3

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PetSmart.com sold the following varieties of dog food in June 2003.
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Let x  be the number of bags of Nature's Recipe Venison Meal & Rice Canine 20 percent protein, y be the number of bags of Nutro Max Natural Dog Food 27 percent protein and z be the number of bags of PetSmart Premier Oven Baked Lamb 25 percent protein a dog breeder buys. He  wants to make 300 pounds of a mix. Then

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Now

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Then 4x+4.725y+7.5z=66.

You get a system

\left\{\begin{array}{l}20x+17.5y+30z=300\\4x+4.725y+7.5z=66.\end{array}\right.

From the first equation z=10-\dfrac{2}{3}x-\dfrac{7}{12}y. Substitute it into the second equation:

4x+4.725y+7.5(10-\dfrac{2}{3}x-\dfrac{7}{12}y)=66.

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