Answer:
decreased drastically over the last five decades
Explanation:
I would say it is that answer because a few decades ago we needed huuuge computers that filled rooms to compute simple tasks. Now we have cellphones, which are basically computers that can fit into the palm of our hands. Our phones can do more than what those huge computers of the past did and they're easier to produce. So cost must have drastically decreased.
Answer:
Following are the program in c++ language
#include <iostream> // header file
using namespace std;// namespace
int main() // main function
{
int num; // variable declaration
long int f=1; // variable declaration
do
{
cout<<"Enter the Positive value:";
cin>>num;
} while(num<0); // i check whether number is non negative or not
while(num>0) // iterating over the loop
{
f=f*num; // calculate the factorial
num--; // decrement the value of num by 1
}
cout<<" factorial is :"<<f; // display the factorial .
return 0;
}
Output:
Enter the Positive value:7
factorial is :5040
Explanation:
Following are the description of the program .
- Read the input by user in the "num" variable of "int" type..
- The do-while will check the enter number is nonnegative number.
- While(n>0) loop is calculating the factorial in the "f" variable .
- Finally display the factorial .
Sound, Audio for engineering sound Quality's.
Answer:
d. an end point of the microflow mendix
Explanation:
In Computer programming, Microflows can be defined as a visual representation of textual program codes based on the Business Process Model and Notation (BPMN), it enables users to express the logic of application.
It is capable of performing various actions such as creating and updating objects, showing pages and making choices.
Microflows cannot be used in offline apps as it basically runs in the runtime server.
A red bullet in a microflow indicates an end point of the microflow mendix.
Answer:
Binary to Gray Code Converter
The logical circuit which converts the binary code to equivalent gray code is known as binary to gray code converter. An n-bit gray code can be obtained by reflecting an n-1 bit code about an axis after 2n-1 rows and putting the MSB (Most Significant Bit) of 0 above the axis and the MSB of 1 below the axis.
The 4 bit binary to gray code conversion table is given in attached file.
