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Andre45 [30]
3 years ago
9

How many solutions does the equation 3(x+2)-10=4x-6+x have?

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:

x=1

Step-by-step explanation:

3(x+2)-10=4x-6+x

3x+6-10=5x-6

3x-5x-4=-6

-2x-4=-6

-2x=-6+4

-2x=-2

2x=2

x=2/2

x=1

KengaRu [80]3 years ago
6 0

Answer: The answer is 1

Step-by-step explanation:

Simplifying

3(x + 2) + -10 = 4x + -6 + x

Reorder the terms:

3(2 + x) + -10 = 4x + -6 + x

(2 * 3 + x * 3) + -10 = 4x + -6 + x

(6 + 3x) + -10 = 4x + -6 + x

Reorder the terms:

6 + -10 + 3x = 4x + -6 + x

Combine like terms: 6 + -10 = -4

-4 + 3x = 4x + -6 + x

Reorder the terms:

-4 + 3x = -6 + 4x + x

Combine like terms: 4x + x = 5x

-4 + 3x = -6 + 5x

Solving

-4 + 3x = -6 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

-4 + 3x + -5x = -6 + 5x + -5x

Combine like terms: 3x + -5x = -2x

-4 + -2x = -6 + 5x + -5x

Combine like terms: 5x + -5x = 0

-4 + -2x = -6 + 0

-4 + -2x = -6

Add '4' to each side of the equation.

-4 + 4 + -2x = -6 + 4

Combine like terms: -4 + 4 = 0

0 + -2x = -6 + 4

-2x = -6 + 4

Combine like terms: -6 + 4 = -2

-2x = -2

Divide each side by '-2'.

x = 1

Simplifying

x = 1

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Answer:

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first random sample size n₁ = 500</em>

Given  Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

<em>First sample proportion </em>

<em>                              </em>p^{-} _{1} = \frac{65}{500} = 0.13

<em>Given second sample size n₂ = 700</em>

<em>Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.</em>

<em>second sample proportion </em>

<em>                              </em>p^{-} _{2} = \frac{133}{700} = 0.19

<em>Level of significance = α = 0.05</em>

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<u><em>Step(ii)</em></u><em>:-</em>

<em>Null hypothesis : H₀: There  is no significance difference between these proportions</em>

<em>Alternative Hypothesis :H₁: There  is significance difference between these proportions</em>

<em>Test statistic </em>

<em></em>Z = \frac{p_{1} ^{-}-p^{-} _{2}  }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }<em></em>

<em>where </em>

<em>         </em>P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2}  }{n_{1}+ n_{2}  } = \frac{500 X 0.13+700 X0.19  }{500 + 700 } = 0.165<em></em>

<em>        Q = 1 - P = 1 - 0.165 = 0.835</em>

<em></em>Z = \frac{0.13-0.19  }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }<em></em>

<em>Z =  -2.76</em>

<em>|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected at 0.05 level of significance</em>

<em>Alternative hypothesis is accepted at 0.05 level of significance</em>

<u><em>Conclusion:</em></u><em>-</em>

<em>There is there is a difference between these proportions at α = 0.05</em>

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