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3 years ago

How many solutions does the equation 3(x+2)-10=4x-6+x have?

Mathematics

2 answers:

Shtirlitz [24]3 years ago

8 0

Answer:

x=1

Step-by-step explanation:

3(x+2)-10=4x-6+x

3x+6-10=5x-6

3x-5x-4=-6

-2x-4=-6

-2x=-6+4

-2x=-2

2x=2

x=2/2

x=1

KengaRu [80]3 years ago

6 0

Answer: The answer is 1

Step-by-step explanation:

Simplifying

3(x + 2) + -10 = 4x + -6 + x

Reorder the terms:

3(2 + x) + -10 = 4x + -6 + x

(2 * 3 + x * 3) + -10 = 4x + -6 + x

(6 + 3x) + -10 = 4x + -6 + x

Reorder the terms:

6 + -10 + 3x = 4x + -6 + x

Combine like terms: 6 + -10 = -4

-4 + 3x = 4x + -6 + x

Reorder the terms:

-4 + 3x = -6 + 4x + x

Combine like terms: 4x + x = 5x

-4 + 3x = -6 + 5x

Solving

-4 + 3x = -6 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

-4 + 3x + -5x = -6 + 5x + -5x

Combine like terms: 3x + -5x = -2x

-4 + -2x = -6 + 5x + -5x

Combine like terms: 5x + -5x = 0

-4 + -2x = -6 + 0

-4 + -2x = -6

Add '4' to each side of the equation.

-4 + 4 + -2x = -6 + 4

Combine like terms: -4 + 4 = 0

0 + -2x = -6 + 4

-2x = -6 + 4

Combine like terms: -6 + 4 = -2

-2x = -2

Divide each side by '-2'.

x = 1

Simplifying

x = 1

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