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3 years ago

Suppose that there are 11 employees in an office. The boss needs to select 5 of the employees to

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

4 0

Answer:

462ways

Step-by-step explanation:

This Is a combination problem, we we are expected to determine the number of possible ways of selecting the numbers of staffs for a business trip

C(n, r) were n= 11

r=5

C(n, r) = n!/(n-r)! r!

C(n, r) = 11!/(11-5)! 5!

C(n, r) = 11!/(6)! 5!

C(n, r) = 11*10*9*8*7*6!/(6)! 5*4*3*2*1

C(n, r) = 11*10*9*8*7/5*4*3*2*1

C(n, r) = 55440/120

C(n, r) = 462

The number of possible ways is 462

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Read 2 more answers

Which expression is the factorization of x2 + 10x + 21?

LiRa [457]

<h2>Solution:</h2>

Equation: x² + 10x + 21

Step 1: Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21

Step 2: Get the new equation bracketed → (x² + 7x) (+3x + 21)

Step 3: Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).

Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)

<h3>Final answer:</h3>

(x+3) (x+7)

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