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2 years ago

Lisa drew a picture of a boat. She used the scale factor 1 inch : 6 feet

Mathematics

1 answer:

kotykmax [81]2 years ago

3 0

Answer:

42 feet

Step-by-step explanation:

if each inch equals 6 feet, and if her drawing is 7 inches long, then 7×6 would equal the auctual length of the boat, which is 42 feet.

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What are the x-intercepts of the graph of the quadratic function

Svetllana [295]

Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.

(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: $0=5x^2+5x-x-1$

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: $0=5x(x+1)-1(x+1)$

Now you can rewrite the equation as: $0=(5x-1)(x+1)$

Now apply zero product property to the factors to solve for x:

$5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1$

The x-intercepts are (1/5 ,0) and (-1,0).

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3 years ago

Given b(x) = |x+4], what is b(-10)? -10 -6 8 14

GREYUIT [131]

Answer:

b(-10) = 6

Step-by-step explanation:

Step 1: Define

b(x) = |x + 4|

b(-10) is x = -10

Step 2: Substitute and Evaluate

b(-10) = |-10 + 4|

b(-10) = |-6|

b(-10) = 6

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3 years ago

Read 2 more answers

A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr

SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

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2 years ago

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Answer:

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anyanavicka [17]

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