We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is
<span>
5 feet. </span>
<span>11 2/8 there is a 1 5/8 between each of them so you keep adding 1 5/8 miles each day.</span>
3 and 18 | 12&18 GCF = 6; 8&24 GCF = 4; 1&3 GCF = 3
----------------------------------------
Define x:
----------------------------------------
Let x be the length of the pool.
Length of the pool and its border = x + 1 + 1
Length of the pool and its border = x + 2
----------------------------------------
Given area = 361 ft², find x:
----------------------------------------
(x+2)² = 361
x+ 2 = √361
x + 2 = 19
x = 19 - 2
x = 17
----------------------------------------
Find Length of the pool:
----------------------------------------
Length of the pool = x = 17 feet
----------------------------------------
Find Area of the pool:
----------------------------------------
Area = 17 x 17
Area = 289 ft²
------------------------------------------------------------
Answer: Area of the pool = 289 ft²
------------------------------------------------------------