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4 years ago

Ok ok THIS is the part 2 to my last question

Mathematics

2 answers:

Scorpion4ik [409]4 years ago

7 0

an = an - 1 + 6 where a1 = 4

cupoosta [38]4 years ago

5 0

$a_1=4\\\\a_2=4+6=10\\\\a_3=10+6=16\\\\a_n=a_{n-1}+6,\ a_1=4$

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If f(x) = (x-6)(x +12), determine the x-intercepts of y = f(-3x). Show your work.

kirill [66]

Explanation is $^{}$ in a file

bit. $^{}$ ly/3gVQKw3

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3 years ago

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Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$

Option C

8 0

3 years ago

John buys a billiard table from a nearby store. The width of the table is 38 inches. What is the

sergij07 [2.7K]

Answer:

76 inches

Step-by-step explanation:

38 multiplied by 2 is 72... since the width(38) is half the length

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3 years ago

What is 1 over 4 + 3 over 4?

artcher [175]

Answer:

Step-by-step explanation:

What is 1 over 4 + 3 over 4?

1/4 + 3/4 =

4/4 =

5 0

3 years ago

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what is the quotient when x3 − 5x2 2x 5 is divided by x − 2? x2 − 3x − 4 x2 − 7x 16 x2 − 3x − 4 − 3 over the quantity of x minus

nekit [7.7K]

The correct answer is: 
x²-3x-4 - $\frac{3}{x-2}$ .

Explanation: 
To divide these polynomials, the dividend, x³-5x²+2x+5, goes under the box, and the divisor, x-2, goes outside of the box.

We first want to find what we multiply x by to make x³; x*x²=x³, so we write x² over -5x² in the box.

Now we multiply our divisor, x-2, by x²: 
x*x²=x³
-2*x²=-2x².

This goes under x³-5x² in the box.

Now we subtract: 
(x³-5x²)-(x³-2x²)=-3x².

This goes below the 2x² we wrote, and we bring down 2x.

Now we see what we multiply x by to make -3x²;
x*-3x=-3x², so we write -3x beside x² in the quotient (at the top).

We multiply our divisor, x-2, by -3x: 
x*-3x=-3x²
-2*-3x=6x.

We write -3x²+6x under our -3x²+2x and subtract:
(-3x²+2x)-(-3x²+6x)=-4x.

Write this below 6x. Bring down +5.

Now we see what we multiply x by to make -4x;
x*-4=-4x, so write -4 beside -3x in the quotient.

Multiply our divisor, x-2, by -4: 
x*-4=-4x;
-2*-4=8;

write -4x+8 below -4x+5 and subtract:
(-4x+5)-(-4x+8)=-3.

This gives us the quotient x²-3x-4 with a remainder of -3, so we write our full answer as x²-3x-4-(3/x-2).

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3 years ago

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