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scoundrel [369]
3 years ago
7

Which of the following equations represents the total cost, C, for the number of sandwiches, S, where each sandwich costs $7?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0
I’m thinking a because your not dividing
Greeley [361]3 years ago
3 0
Total cost is C

No of sandwiches is S

Each S costs $7

So equation is number 2 (C = 7S)

Hope this helps
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Help<br> 1<br> A /<br> 7 (x + 2) -5 = 30
DaniilM [7]

Answer:

x = 3

Step-by-step explanation:

Given

7(x + 2) - 5 = 30 ( add 5 to both sides )

7(x + 2) = 35 ( divide both sides by 7 )

x + 2 = 5 ( subtract 2 from both sides )

x = 3

3 0
3 years ago
How do you write  35 4  as a percentage
GenaCL600 [577]
354 as a percentage is 354%
35.4 as a percentage is 35.4%
8 0
3 years ago
Consider the procedure used below to solve the given equation.
muminat
The first mistake was made in step 1 because they took out the x’s it should be 10x-25+2x+8=43
5 0
3 years ago
The quadratic function d= -4x+1,100 models a snowboarder's distance, in feet, from the bottom of a hill x seconds after the snow
Fynjy0 [20]

Answer:

16 seconds (Approximately)

Step-by-step explanation:

Given:

The function that gives the distance of snowboarder from the bottom of hill with time 'x' is:

d=-4x^2+1100

Final position of the snowboarder is d=100\ ft

Now, plugging in 100 for 'd' and solving for 'x', we get:

100=-4x^2+1100

Adding -1100 both sides, we get:

100-1100=-4x^2+1100-1100\\-1000=-4x^2

Dividing both sides by -4, we get:

\frac{4x^2}{4}=\frac{1000}{4}\\x^2=250

Taking square root and neglecting the negative root as time can't be negative. So,

\sqrt{x^2}=\sqrt{250}\\x=5\sqrt{10}=15.8\ s\approx 16\ s

Therefore, after 16 seconds, the snowboarder will be at a distance of 100 ft from bottom of hill.

7 0
3 years ago
For which operations is the set {0, 1} closed?
velikii [3]
0 × <span>0 = 0
0 </span>× <span>1 = 0
1 </span>× <span>1 = 1

Which means multiplication is closed under {0, 1}

</span><span>1 </span>÷ <span>1 = 1
0 </span>÷ <span>1 = 0
</span>
Division is not closed under {0, 1}

1 + 1 = 2

Addition is not closed under {0, 1}

0 - 1 = -1

Subtraction is not closed under {0, 1} either



So it's only A. Multiplication which is closed under {0, 1}
5 0
4 years ago
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