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enyata [817]
3 years ago
12

Give your answer as a mixed number 4 3/7 - 2 5/7 get brainliest urgent plz help

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:

1\frac{5}{7}

Step-by-step explanation:

4\frac{3}{7} -2\frac{5}{7}

Step 1. Simplify left side 4*7+3 , Right Side 2*7+5

=\frac{31}{7} -\frac{19}{7} = \frac{12}{7}

Step 2. Re-write 12/7 as mixed number

\frac{12}{7} = 1\frac{5}{7}

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Lisa’s age is 4 years older than three times sammy’s Age. Lisa is 28 years old let s represent sammy’s Age
mel-nik [20]

Answer:

Sammy is 8 years old

Step-by-step explanation:

3s + 4 = 28 is the equation you need to use you have to get s on its own to find Sammy's age

3s + 4 = 28    subtract 4 from both sides

3s = 24      divide both sides by 3

s = 8      Sammy is 8 years old

3 0
3 years ago
Read 2 more answers
Find the length of the radius of a sphere with a surface area of 5541.77 cm2.
ladessa [460]
The area of a sphere: A  = 4.π.R²

A= 5541.77 → 5541.77 = 4.π.R²

R² = (5541.77)/(4.π)
R² = 441; → R =√441; R = 21 cm

6 0
3 years ago
Given the function f(x)=x+5-1 choose the correct domain
ElenaW [278]

Answer:

The domain of the function is all real numbers.

Step-by-step explanation:

I graphed the function on the graph below.

If this answer is correct, please make me Brainliest!

6 0
3 years ago
A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig
Vaselesa [24]

Answer:

a) Depth changing rate of change is 0.24m/min, When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of 0.17m/min, When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them \frac{3.5}{10} =\frac{a}{h}, then a=0.35h.

a) As we have that volume is V=\frac{1}{2} 2ahL=ahL, then V=(0.35h^{2})L, so we can derivate it \frac{dV}{dt}=2(0.35h)L\frac{dh}{dt} due to the chain rule, then we clean this expression for \frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt} and compute with the knowns \frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min, is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is 2a=0.7h, we can derivate it and obtain \frac{da}{dt}=0.7\frac{dh}{dt}  =0.7*0.24m/min=0.17m/min The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0
3 years ago
Solve the equation by completing the square
Andrews [41]

Answer:

b1=2\sqrt{46} +10

b2=10-2\sqrt{46}

Step-by-step explanation:

4 0
3 years ago
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