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MissTica
3 years ago
15

HELP!!!!!!!!!!!!!!!!!!  What is the perimeter of the figure shown on the coordinate plane?

Mathematics
1 answer:
densk [106]3 years ago
7 0
You can look at those dots, for example, you see (2,8) and (2,2) then look at y and the difference is 6. so if you see it like that, (2,8) and (5,8) is 3, (5,8) and (5,4) would be 4, (5,4) and (8,4) would be 3, (8,4) and (8,2) would be 2, and lastly (2,2) and (8,2) is 6
Now you add all of them up which will be 6+3+4+3+2+6 = 24
so the perimeter of this figure is 24<span />
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here a subtraction problem that has been solved incorrectly what is the right answer for 74-25=59 but do it in the addition sent
madam [21]

Answer:

the equation is wrong

Step-by-step explanation:

=> 74-25=59

since 74 - 25 equals to 59 in order to find the addition sentence that will check the subtraction problem is true and 59 and 3/5 or you can add add 59 and 25 to check if the problem was solved correctly

=> 59+25

add 59 to 25

=> 84

this means the question is wrong

5 0
2 years ago
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Name a multiple of 13 that is between 30 and 100.
emmainna [20.7K]

Answer:

39

Step-by-step explanation:

just did 13 plus 13 plus 13

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3 years ago
The sum of two numbers is 19 and there difference is 7 what are the two numbers
Zielflug [23.3K]

Answer:

The two numbers are 13 and 6.

Step-by-step explanation:

x+y=19

x-y=7

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2x=26

x=26/2

x=13

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y=19-13

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x=13, y=6.

5 0
3 years ago
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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
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Can someone help me with this equation?
navik [9.2K]

Answer:

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Step-by-step explanation:

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5 0
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