What is the perimeter of rectangle EFGH?
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Answer:
Possible values of dimensions are (24,16,2) or (24,8,4)
Step-by-step explanation:
We are given the volume of the Cuboid and length . We are required to find the possible values of width and height from this information.
Let us say that the width is x and height is y
Length = 24
Volume of a cuboid = length * width * height
Volume = 768
768=24*x*y
xy=32
Now the possible factors of 32
32=1*32 ( Which shall not be taken into consideration as length is already given as 24 and width or height can not be more length)
32=2*16
32=4*8
Hence the possible values width are 8, 16 and that of height 4 and 2
Hence the possible values of dimensions are (24,16,2) or (24,8,4)