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mario62 [17]
3 years ago
13

Use the confidence level and sample data to find a confidence interval for estimating the population mu. Round your answer to th

e same number of decimal places as the sample mean. 37 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 10.3 pounds and a standard deviation of 2.4 pounds. What is the 95% confidence interval for the true mean weight, mu, of all packages received by the parcel service?
a. 9.6 lb < mu < 11.0 lb.
b. 9.4 lb < mu < 11.2 lb.
c. 9.5 lb < mu < 11.1 lb.
d. 9.3 lb< mu < 11.3 lb .
Mathematics
1 answer:
inysia [295]3 years ago
7 0

Answer:

c. 9.5 lb < mu < 11.1 lb.

Step-by-step explanation:

Confidence interval can be stated as M±ME where

  • M is the sample mean (10.3)
  • ME is the margin of error

margin of error (ME) around the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic in 95% confidence level (1.96)
  • s is the standard deviation of the sample (2.4)
  • N is the sample size (37)

Putting thesenumbers in the formula we get:

ME=\frac{1.96*2.4}{\sqrt{37} } ≈ 0.7733 ≈ 0.8

Then the 95% confidence interval would be 10.3 ± 0.8

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Answer:

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Step-by-step explanation:

We are looking for side h, which is opposite of the observer. We know that the side adjacent to the observer is 500 feet. We also know that the angle from the observer to the bird is 39°. Because we have these values, SOH CAH TOA tells us that we should use tangent, opposite over adjacent.

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