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aalyn [17]
3 years ago
9

√3 /√6 rationalise denominator and simplify

Mathematics
1 answer:
melomori [17]3 years ago
7 0

Answer:

\frac{ \sqrt{2} }{2}  \\

Step-by-step explanation:

\frac{ \sqrt{3} }{ \sqrt{6} }  \\  \frac{ \sqrt{3} }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} }  \\   \frac{ \sqrt{3 \times 6} }{ \sqrt{ {6}^{2} } }  \\  \frac{ \sqrt{18} }{6}  \\  \frac{ \sqrt{2 \times 9} }{6}  \\  \frac{3 \sqrt{2} }{6}  \\  \frac{ \sqrt{2} }{2}

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Hello,

Since 3sin x-4sin^3x=sin (3x)  (*****)
3sin x-4sin^3x=-1
==>sin (3x)=-1
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==>x=π/2+2kπ/3, k being an integer

(*****)
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4 years ago
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