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Inessa05 [86]
2 years ago
9

Assuming the volume of a trigonal prism, who has a side of 10cm and a length of 20 cm, is 866cm^3, what is its surface area?

Mathematics
1 answer:
Leno4ka [110]2 years ago
6 0

The surface area of the triangular prism is 686.6 cm².

Step-by-step explanation:

Step 1:

The volume of a triangular prism can be determined by multiplying its area of the triangular base with the length of the prism.

The base triangle has a base length of 10 cm and assume it has a height of h m.

The volume of the prism= \frac{1}{2} (b)(h) (length) = \frac{1}{2} (10)(h)(20) = 866.

h = \frac{866(2)}{10(20)} = 8.66.

The height of the triangle is 8.66 cm.

Step 2:

The surface area of the triangle is obtained by adding all the areas of the shapes in the prism. There are 2 triangles and 3 rectangles in a triangular prism.

The triangles have a base length of 10 cm and a height of 8.66 cm. A triangles area is half the product of its base length and height.

The rectangles all have a length of 20 cm and a width of 10 cm. The area of a rectangle is the product of its length and width.

The area of the 2 triangles = 2 [\frac{1}{2} (10)(8.66)] = 86.6.

The area of the 3 rectangle = 3[(20)(10)] = 600.

Step 3:

The surface area of the triangular prism = 86.6 + 600 = 686.6.

The surface area of the prism is 686.6 cm².

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Answer:

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Step-by-step explanation:

1 in = 1500 miles

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2 years ago
The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b
Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

b) p_v =P(z>2.32)=0.0102  

c) So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

For this case the statistic is given by z_{calc}= 2.32

Part b: Statistical decision  

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The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.32)=0.0102  

Part c

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0
3 years ago
QUICKLY PLEASE!!<br> 18POINTS!<br> 6(3p – 2) = 24
Gekata [30.6K]

Answer:

p= 2

Step-by-step explanation:

So first you want to distribute the 6 to 3p-2 which basically means multiply

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* remember a negative and a positive equal a negative*

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so p = 2

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