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olchik [2.2K]
4 years ago
7

An animal shelter spends $4.50 per day to care for each bird and $8.50 per day to care for each cat. Dominic noticed that the sh

elter spent $175.00 caring for birds and cats on Monday. Dominic found a record showing that there were a total of 22 birds and cats on Monday. How many birds were at the shelter on Monday?
Mathematics
1 answer:
Nimfa-mama [501]4 years ago
3 0

Answer:

Step-by-step explanation:

4.5b + 8.5c = 175

b + c = 22.......b = 22 - c

4.5(22 - c) + 8.5c = 175

99 - 4.5c + 8.5c = 175

-4.5c + 8.5c = 175 - 99

4c = 76

c = 76/4

c = 19......there are 19 cats

b + c = 22

b + 19 = 22

b = 22 - 19

b = 3 <==== there are 3 birds

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nata0808 [166]

Answer:

π/3

Step-by-step explanation:

the explanation is as in the picture

5 0
3 years ago
A $64 item is marked up to $80. Find the percent markup.
swat32

Answer:

The Markup was by 25%

Step-by-step explanation:

The answer is 25% because 25% of 64 is 16

25% * 64 = 16

64 + 16 = 80

So, the price markup was by 25%

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
-10 x + 4 = 52 x=___ help
Strike441 [17]

Answer: x=-4.8

Step-by-step explanation:

Given

-10x+4=52

Subtract 4 on both sides

-10x+4-4=52-4

-10x=48

Divide -10 on both sides

-10x/-10=48/-10

x=-4.8

Hope this helps!! :)

Please let me know if you have any questions

7 0
3 years ago
Read 2 more answers
Need help with my work!
malfutka [58]

Answer:

look at explanation

Step-by-step explanation:

1) 3d - 8

2) g - 2 = 14

3) 7 + z

4) 6 + s = 2/5x

5) 10 - x

6) 5a - 3

7) 9 + s

8) h - 9

hope this helps! :)) xoxo raina *

7 0
3 years ago
Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
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