All categories

3 years ago

Solve for the m in the equation

Mathematics

1 answer:

velikii [3]3 years ago

5 0

Answer:

$m = 15$

Step-by-step explanation:

$\frac{m}{9 } + \frac{2}{3} = \frac{7}{3}$

Multiply both sides of the equation by 99, the least common multiple of 9,39,3.

m + 6 =21

Subtract 6 from both sides.

m = 21 - 6

Subtract 6 from 21 to get 15.

m=15

You might be interested in

This year consumers purchased 7,234,267,990 bottles of water. Last year consumers purchased 2,000,900,999 bottles of water. Whic

torisob [31]

Answer:

B. 9,000,000,000

Step-by-step explanation:

From the given information:

We are to determine the best estimate of the number of bottles sold this year and last year.

The best estimate means rounding up to the nearest whole number.

Given that:

7,234,267,990 bottles of water were purchased this year

2,000,900,999 bottles of water were purchased last year

The estimate of the bottles sold this year and last year from the above value is:

= 7,000,000,000 + 2,000,000,000

= 9,000,000,000

4 0

3 years ago

Is 1.9 < 1.39 which comparison is true?

alexandr1967 [171]

Answer:

1.9 is greater than 1.39 if that's what your asking?

7 0

2 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$