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3 years ago

In which basic function does the computer save information

Computers and Technology

1 answer:

fiasKO [112]3 years ago

6 0

Answer:

Storage

Explanation:

At a fundamental level, computers operate through these four functions: input, output, processing, and storage. Input: the transfer of information into the system (e.g., through a keyboard). Output: the presentation of information to the user (e.g., on a screen). Processing: the retrieval or manipulation of information into a new form (e.g., results from a search engine). Storage: the storing or preservation of information for later use (e.g., files stored on a hard drive).

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Write a program that creates a two-dimensional array named height and stores the following data:

antiseptic1488 [7]

Answer:

Explanation:

The following code is written in Java and it simply creates the 2-Dimensional int array with the data provided and then uses the Arrays class to easily print the entire array's data in each layer.

import java.util.Arrays;

class Brainly {

public static void main(String[] args) {

int[][] arr = {{16, 17, 14}, {17, 18, 17}, {15, 17, 14}};

System.out.print(Arrays./*Remove this because brainly detects as swearword*/deepToString(arr));

}

4 0

3 years ago

Read 2 more answers

What role does the automated surface observing system.

Ilya [14]

Answer: The ASOS systems serves as the nation's primary surface weather observing network. ASOS is designed to support weather forecast activities and aviation operations

6 0

2 years ago

Read 2 more answers

The Beaufort Wind Scale is used to characterize the strength of winds. The scale uses integer values and goes from a force of 0,

TEA [102]

Answer:

ranforce = randi([0, 12]);

if (ranforce == 0)

disp('There is no wind')

else if(ranforce>0 && ranforce <7)

disp('There is a breeze')

else if(ranforce>6 && ranforce <10)

disp('This is a gale')

else if(ranforce>9 && ranforce <12)

disp('It is a storm')

else if(ranforce==12)

disp('Hello, Hurricane!')

end

Explanation:

Replace all switch case statements with if and else if statements.

An instance is:

case {7,8,9}

is replaced with

else if(ranforce>9 && ranforce <12)

All other disp statements remain unchanged

5 0

3 years ago

What is the reason of non-deterministic (indeterminate) behavior of concurrent programs?

murzikaleks [220]

Answer: Concurrent programs are the programs that execute at the same point of time. They are simultaneous in nature with other concurrent programs.They are executed with the help of threads to achieve the concurrency without the issue of scheduling. They are consider long running programs.

The program that has the low execution time compared with all other programs gets executed first.If the case of no progress is seen then another thread is executed.This type of execution gives the non- deterministic situation in which the possibility of leading completion of any particular program cannot be determined.

5 0

3 years ago

Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r

kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

INVOKE Str_find,ADDR target, ADDR source

mov position,eax

jz wasfound ; ZF=1 indicates string found

mov edx,OFFSET str3 ; string not found

call WriteString

jmp quit

wasfound: ; display message

mov edx,OFFSET str1

call WriteString

mov eax,position ; write position value

call WriteDec

mov edx,OFFSET str2

call WriteString

quit:

exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

; to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

INVOKE Str_length,pTarget ; get length of target

mov lenTarget,eax

INVOKE Str_length,pSource ; get length of source

mov lenSource,eax

mov edi,OFFSET target ; point to target

mov esi,OFFSET source ; point to source

; Compute place in target to stop search

mov eax,edi ; stop = (offset target)

add eax,lenTarget ; + (length of target)

sub eax,lenSource ; - (length of source)

inc eax ; + 1

mov stop,eax ; save the stopping position

; Compare source string to current target

cld

mov ecx,lenSource ; length of source string

L1:

pushad

repe cmpsb ; compare all bytes

popad

je found ; if found, exit now

inc edi ; move to next target position

cmp edi,stop ; has EDI reached stop position?

jae notfound ; yes: exit

jmp L1 ; not: continue loop

notfound: ; string not found

or eax,1 ; ZF=0 indicates failure

jmp done

found: ; string found

mov eax,edi ; compute position in target of find

sub eax,pTarget

cmp eax,eax ; ZF=1 indicates success

done:

ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0

3 years ago