Answer:
import java.awt.Point;
public class Line{
private Point point1, point2;
public Line(Point p1, Point p2){
point1 = p1;
point2 = p2;
}
public Point getP1(){
return point1;
}
public Point getP2(){
return point2;
}
public String toString(){
return "[( The " + point1.x + "," + point1.y + "), (" + point2.x + "," + point2.y +")]";
}
public static void main(String args[]){
Line lineObj = new Line(new Point(7,9), new Point(6,2));
System.out.println(lineObj.toString());
}
}
Explanation:
- Declare the points inside the class Line.
- Initialize the getters and setters method for the class.
- Define a toString method that returns the information in a formatted manner.
- Inside the main method, initialize an object with some values.
- Display the information by calling the toString method.
Answer:
a.) Incoming packets can be placed in the buffer and played back without the jitter.
b.) Buffering would increase the latency because there would be a delay in time when the packets enter the buffer and the time is released.
Explanation:
Jitter is referred technically as a packet delay variations.
It is variation in the periodicity of periodic events or a signal from target or the true frequency.
Answer:
Option (a)
Explanation:
It is true that managers takes some interviews and some tests which include questions which are able to identify the capabilities of the employee. Their field of expertise can be known by these tests which helps in which project they should put under where their skills will bloom and they can be more efficient. It helps manager to know if the employee is the best fit for their company or not.
Answer:
Step 1: Do Some Research & Conceptualize Your Game. ...
Step 2: Work On A Design Document. ...
Step 3: Decide Whether You Need Software. ...
Step 4: Start Programming. ...
Step 5: Test Your Game & Start Marketing
Answer:
a) The method runs infinitely and causes a StackOverflowError.
// Return the factorial for a specified index
public static long factorial(int n)
{
if (n == 0)
return 1;
else
return n * factorial(n - 1);
}
b) Invoking factorial(2) returns 2.
// Return the factorial (2)
public static long factorial(int 2)
{
if (n == 2)
return 2;
else
return 2 * factorial(3 - 1);
}
c) Invoking factorial(1) returns 1.
// Return the factorial(1)
public static long factorial(int 1)
{
if (n == 1)
return 1;
else
return 1 * factorial(1 - 1);
}
d) Invoking factorial(0) returns 0.
// Return the factorial(0)
public static long factorial(int 0)
{
if (n == 0)
return 0;
else
return 0 * factorial(0 - 1);
}
Explanation:
