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Flauer [41]
4 years ago
9

Suppose a researcher is studying a population that has a mean of μ=38.6 and a standard deviation of σ=1.1. The researcher studie

s a simple random sample of size n = 200. According to the central limit theorem, what is the approximate standard deviation of the sampling distribution of the mean? Round the answer to the nearest thousandth if needed.
Mathematics
1 answer:
Alenkinab [10]4 years ago
8 0

Answer:

The approximate standard deviation of the sampling distribution of the mean is 0.078

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 1.1, n = 200.

According to the central limit theorem, what is the approximate standard deviation of the sampling distribution of the mean?

s = \frac{1.1}{\sqrt{200}} = 0.078

The approximate standard deviation of the sampling distribution of the mean is 0.078

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