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Flauer [41]
3 years ago
9

Suppose a researcher is studying a population that has a mean of μ=38.6 and a standard deviation of σ=1.1. The researcher studie

s a simple random sample of size n = 200. According to the central limit theorem, what is the approximate standard deviation of the sampling distribution of the mean? Round the answer to the nearest thousandth if needed.
Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

The approximate standard deviation of the sampling distribution of the mean is 0.078

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 1.1, n = 200.

According to the central limit theorem, what is the approximate standard deviation of the sampling distribution of the mean?

s = \frac{1.1}{\sqrt{200}} = 0.078

The approximate standard deviation of the sampling distribution of the mean is 0.078

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Answer:

31-19=12°F

12°F

Step-by-step explanation

If it was 19 degrees on Monday and 31 degrees on Tuesday you have to see how much did it go up in temp. So..

the difference between 19 and 31 is 12, so that means it went up by 12°F.

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Read 2 more answers
How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

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Subtract 8x from both sides.

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Add 12 to both sides.

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The real numbers are the only solution we can have.


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What is the question that u need help with
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