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2 years ago

There are 125 animals at the shelter. 15 get adopted. What % of the animals got adopted?

Mathematics

2 answers:

Travka [436]2 years ago

8 0

Answer:

12%.

Step-by-step explanation:

That would be (15/125) * 100

= 1500/125

= 12%

ycow [4]2 years ago

4 0

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

Percentage means out of hundred
to find percentage we need do is juz' multiply given data with 100
1st you all need to do is convert given fraction into decimal
then multiply it with 100 to find percentage

★ Here given in question:-

total numbers of animals at the shelter is 125
then, numbers of animals adopted

$\rule{70mm}{2.9pt}$

soo

$\sf ➤ \: \frac{15}{125} \\ \sf➤ \: \cancel \frac{15}{125} \\ \sf ➤ \: 0.12$

soo decimal form = 0.12

☆ Now finding percentage

$\sf➤0.12 \times 100 \\ ➤ \: 10 \%\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\rule{70mm}{2.9pt}$

☆ Soo the animals got adopted in percentage is

$\large\pink{\underline{ \underline{ \boxed{ \sf{✰\:12\%✓}}}}}$

$\rule{70mm}{2.9pt}$

Hope it helps!

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3 years ago

During halftime of a basketball game, a sling shot launches T-shirts at the crowd. A T-shirt is launched from a height of 4 f

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Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is $4 + 64\cdot t - 16 \cdot t^{2}$

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

$h = 4 + 64\times 2 - \frac{1}{2} \times 32 \times 2^{2}$

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

$h =4 + 64\cdot t - \frac{1}{2} \times 32 \cdot t^{2} = 4 + 64\cdot t - 16 \cdot t^{2}$ .

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