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Fed [463]
3 years ago
10

Suppose a quiz has 12 multiple choice questions. Each question has 4 answer choices. If a student takes the quiz and randomly gu

esses on every question.... Find the probability the student gets between 1 and 6, exclusive, questions correct.
Mathematics
1 answer:
Gnoma [55]3 years ago
3 0

The probability that the student gets between 1 and 6, exclusive, questions correct will be 0.7872...

<em><u>Explanation</u></em>

If the probability of success is p , then the probability of r successes in n trials will be......

P = ^nC_{r}*(p)^r (1-p)^n^-^r

Here, the quiz has total 12 questions and each question has 4 answer choices. So, n=12 and p=\frac{1}{4}= 0.25

The student gets between 1 and 6, exclusive, questions correct. It means <u>there can be 2 or 3 or 4 or 5 questions as correct</u>. So....

The probability of 2 or 3 or 4 or 5 questions correct will be:

=^1^2C_{2}*(0.25)^2(1-0.25)^1^0 + ^1^2C_{3}*(0.25)^3(1-0.25)^9 +^1^2C_{4}*(0.25)^4(1-0.25)^8+^1^2C_{5}*(0.25)^5(1-0.25)^7\\ \\ =0.2322...+0.2581...+0.1935...+0.1032... \\ \\ =0.7872...

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2.5 x 10^{15} miles

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We are given that 1 light year ≈ 5.9 x 10^{12} miles so:

  • 4.3 x 10² light year · <u>5.9 x </u>10^{12}<u> miles </u>                                                                                                
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Multiply 4.3 an 5.9 and round to 2 significant digits then add the exponents:

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This is not the scientific notation since the number is not between 0 and 10 so we move the decimal point by 1 place to the left. We then add 1 to the exponent to obtain the final answer:

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