Answer: below in picture
explanation: also in picture
Y=mx+b where m=-6, x=-2, and y=-3. Substituting these values in would result in -3=(-6)(-2)+b, which would simplify to -3=12+b, and further to b=-15. This would mean the y intercept is equal to -15, or (0,-15). To check, (-6)*(-2)-15 is in fact equal to -3, thus allowing easy identification of a graph, which will cross the y axis at -15 and decrease in y-value by 6 with every increase in x-value.
Answer:
2x3 - 3x + 4
———————
x2
Step-by-step explanation:
Step 1 :
2
Simplify ——
x2
Rewriting the whole as an Equivalent Fraction :
4.1 Adding a fraction to a whole
Rewrite the whole as a fraction using x2 as the denominator :
x x • x2
x = — = ——————
1 x2
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 5.00
-1 2 -0.50 5.25
-2 1 -2.00 -6.00
-4 1 -4.00 -112.00
1 1 1.00 3.00
1 2 0.50 2.75
2 1 2.00 14.00
4 1 4.00 120.00
Polynomial Roots Calculator found no rational roots
Final result :
2x3 - 3x + 4
————————————
x2
Processing ends successfully
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Answer:
The rental cost for Company A and Company B will be the same after 500 miles
Step-by-step explanation:
The total cost of renting a truck from Company A can be expressed as;
Total rental cost(Company A)=Cost per day+Total rate
where;
Cost per day=70
Total rate=rate per mile×number of miles (m)=(0.5×m)=0.5 m
replacing;
Total rental cost(Company A)=70+0.5 m...equation 1
2. The total cost of renting a truck from Company B can be expressed as;
Total rental cost(Company B)=Cost per day+Total rate
where;
Cost per day=20
Total rate=rate per mile×number of miles (m)=(0.6×m)=0.6 m
replacing;
Total rental cost(Company B)=20+0.6 m...equation 2
Equating equation 1 to equation 2
70+0.5 m=20+0.6 m
0.6 m-0.5 m=70-20
0.1 m=50
m=50/0.1
m=500 miles
The rental cost for Company A and Company B will be the same after 500 miles
Answer:
0.91517
Step-by-step explanation:
Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.
Let A - the event passing in SAT with atleast 1500
B - getting award i.e getting atleast 1350
Required probability = P(B/A)
= P(X>1500)/P(X>1350)
X is N (1100, 200)
Corresponding Z score = 
