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mel-nik [20]
3 years ago
13

Pleaseee help I’m struggling

Mathematics
2 answers:
shutvik [7]3 years ago
6 0

Answer:

slope=3

Step-by-step explanation:

(1, -2) (3, 4)

x1 y1 x2 y2

formula= <u>y2-y1</u>

x2-x1

=

<u>4-(-2)</u><u> </u><u>=</u><u> </u><u>6</u>

3-1 = 2

6/2=3

Lelechka [254]3 years ago
4 0

Answer:

Slope=3

Step-by-step explanation:

It tells you how to do it

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A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
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Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

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