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3 years ago

14

Solve -3/7h=6 Can anyone help me with this??

1 answer:

Ghella [55]3 years ago

5 0

$-\dfrac{3}{7}h=6\ \ \ \ |\cdot\left(-\dfrac{7}{3}\right)\\\\\left(-\dfrac{\not7^1}{\not3_1}\right)\cdot\left(-\dfrac{\not3^1}{\not7_1}\right)h=-\dfrac{7}{\not3_1}\cdot\not6^2\\\\h=-7\cdot2\\\\\boxed{h=-14}$

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Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

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The first five terms in the sequence is at n=1,2,3,4,5

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For n=2,

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For n=3,

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For n=4,

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For n=5,

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$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

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3 years ago