So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
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S=(k+1)(k)
so the sum will be equal to
S=

so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
A - 24!
-21 as its true value is 21
-3 as its true value is 3
if you add them together you get 24!
Hope this helped ^^
Answer:
4
Step-by-step explanation:
10^2/5^2
Do the exponents first
10 to the 2nd power is 100
5 to the 2nd power is 25
100/25
100 divided by 25 is 4
So the answer is 4
Hope this helps!
Answer:
Step-by-step explanation:
y= -5x/2+1
Step-by-step explanation:
5×6'3n=20
30'3n=20
3n=20-30
3n/3= -10/3
n= -3