Answer:
8 by 12 units
Step-by-step explanation:
Let w represent the width of the rectangle. Then the length is 1.5w. The perimeter is 4 more than 3 times this, so is (3(1.5w) +4) = 4.5w+4
The perimeter is given by the formula ...
P = 2(length + width)
Filling in the given values for the variables, we have ...
4.5w +4 = 2(w +1.5w)
4 = 0.5w . . . . . . subtract 4.5w and collect terms
8 = w . . . . . . . . . multiply by 2
length = 1.5×8 = 12
The rectangle is 8 units wide and 12 units long. The perimeter is 40 units.
107 = 7 -2 (7b - 1)
First, distribute -2 to all terms within the parenthesis
-2(7b - 1) = -14b + 2
107 = 7 -14b + 2
Combine like terms
107 = -14b (+7 + 2)
107 = -14b + 9
Isolate the b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
Subtract 9 from both sides
107 (-9) = -14b + 9 (-9)
107 - 9 = -14b
98 = -14b
Isolate the b. Divide -14 from both sides
(98)/-14 = (-14b)/-14
98/-14 = b
b = −7
-7 is your answer
hope this helps
Answer:
20 inches²
Step-by-step explanation:
perimeter = 8 + 3 + 5 + 4
= 20 inches²
Answer:
-11-12h
Step-by-step explanation:
X 1 = 3 * cos 120° = - 3 cos 60° = - 3/2 = - 1.5
y 1 = 3 * sin 120° = 3 sin 60° = 3√3 / 2 = 2.598
x 2 = 0.5 * cos 49° = 0.328
y 2 = 0.5 * sin 49° = 0.37735479
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d = [( x 2 - x 1 )² + ( y 2 - y 1 )²]^(1/2)
d = [ ( 0.328 + 1.5 )² + ( 0.37735479 - 2.598) ] ^(1/2)
d = ( 3.341584 +4.931265 )^(1/2)
Answer: The distance is :
d = 2.876256
