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Tomtit [17]
3 years ago
7

A cone has a radius of 5 cm and a slant height of 10 cm. The area of the base of the cone is π cm2. The lateral area of the cone

is π cm2. The surface area of the cone is π cm2.
Mathematics
2 answers:
taurus [48]3 years ago
7 0

Answer:

base area: 25π cm^2

lateral area = 50π cm^2

surface area = 75π cm^2

Step-by-step explanation:

Put the given numbers into the appropriate formula and do the arithmetic.

The base area is the area of a circle, given by the formula ...

A = πr^2

A = π(5 cm)^2 = 25π cm^2

The lateral area is half the product of the circumference and the slant height. It is given by the formula ...

LA = (1/2)(2πrs) = πrs . . . . where s is the slant height

LA = π(5 cm)(10 cm) = 50π cm^2

The total surface area is the sum of the base area and the lateral area:

surface area = 25π cm^2 + 50π cm^2 = 75π cm^2

AysviL [449]3 years ago
6 0

Answer:

A cone has a radius of 5 cm and a slant height of 10 cm.

The area of the base of the cone is 25π cm2.

The lateral area of the cone is 50π cm2.

The surface area of the cone is 75π cm2.

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Answer:

<h3>A) 204m</h3><h3>B) 188m</h3>

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v  = 0

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t = 96/32

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Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

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h(3) = 144 + 60

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h(2) = 188m

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