Ask question

Ask question

All categories

LUCKY_DIMON [66]

3 years ago

5

A bag has 4 yellow, 6 red, 2 green, and 8 purple marbles . What is the probability of picking a purple marble, replacing it, and

then picking another purple marble

2 answers:

Brut [27]3 years ago

8 0

The probability is 7/19

Ostrovityanka [42]3 years ago

3 0

7/19 is the answer because your replacing the purple marble and it became 7 all u do is add them

You might be interested in

Plz Help! 30 Points!

Ira Lisetskai [31]

45.2 is the constant hope this helps! please give branliest

4 0

3 years ago

Read 2 more answers

Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b

goblinko [34]

So 4 inches diameter result the radius is 4/2 = 2 inches

area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared

volume = area of base *height

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed

hope this will help you

3 0

3 years ago

Effectus [21]

A is the correct choice

3 0

2 years ago

Rename each pair of fractions with common denominator <br> 1/4 and 2/3

GrogVix [38]

3/12 and 8/12

The common denominator is 12

5 0

3 years ago

Read 2 more answers

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

3 years ago

Read 2 more answers